Jon noeds 1/3 cup of

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

5 0

Answer: 1 1/12

Step-by-step explanation:

1/3 + 3/4 =

1/3 x 4= 4/12

3/4 x 3 = 9/12

9/12 + 4/12 = 13/12 = 1 1/12

You might be interested in

PLEASE HELP THIS IS TIMED<br> WHAT IS THE FOLLOWING SUM FIRST ONE IS QUESTION THE REST ARE CHOICES

murzikaleks [220]

$\sqrt[3]{125x^{10}y^{13}}+\sqrt[3]{27x^{10}y^{13}}\\\\\sqrt[3]{125*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}+\sqrt[3]{27*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}\\\\\\\sqrt[3]{125}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}+\sqrt[3]{27}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}\\\\\\5*x*x*x*\sqrt[3]{x}y*y*y*y*\sqrt[3]{y}+3*x*x*x*\sqrt[3]{x}*y*y*y*y*\sqrt[3]{y}\\\\5x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}+3x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}\\\\5x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}+3x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{xy}$