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matrenka [14]
2 years ago
12

Grade 9 maths!!! Due tonight

Mathematics
1 answer:
Artyom0805 [142]2 years ago
3 0

Answer:

a. 7 by 21

b. a(-12, 2), b(-12, -5), c(9, -5)

Step-by-step explanation:

AD is 3 times the length of AB. X can be the length of AB. Then 3x would be the length of AD. The perimeter is 56, which would also be 3x + x + 3x + x which is 8x. This gives us 8x = 56, meaning that x is 7, or the length of AB is 7. Because AD is 3 times the length of AB (which is 7), AD = 21. Therefore, the dimensions of the rectangle ABCD is 7 by 21.

Coordinates of A have to be 21 units away from D since AD = 21. It goes in the left direction, meaning that 21 is subtracted from 9 (since this is a horizontal edge involving x coordinates) while the y value remains the same. The result is (-12, 2). For coordinate B, it has to be 7 units away from A downwards since AB = 7. This means that you subtract 7 from 2 (involving only the y coordinates), resulting in (-12, -5). For coordinate C, it has to be 21 units from B since BC = AD = 21.  Because C is right compared to B, you have to add 21 to -12 (involving only the x coordinate) resulting in (9, -5).

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Step-by-step explanation:

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2 years ago
the Marked price of an article is rupees 1600 if it is sold for rupees 1420 what is the discount rate​
Naya [18.7K]

Answer:

1600-1420= 180

Step-by-step explanation:

Given that

The Marked price of an article is rupees 1600 if it is sold for rupees 1420 then what is the discount rate

1600-1420

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3 years ago
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Mona's math certificate is 10 inches tall and 14 inches wide. Mona wants to put the certificate in a fancy frame that costs $1.0
swat32

Answer:

$48.96

Step-by-step explanation:

Given data

Length= 10inches

Width=14 inches

Let us find the perimeter of the  certificate

P=2L+2W

P= 2*10+2*14

P=20+28

P= 48 inches

Hence if 1 inche cost $1.02

Then 48 inches will cost x

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x= 48*1.02

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A research study investigated differences between male and female students. Based on the study results, we can assume the popula
garri49 [273]

Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = 0.5.
  • Sample of 100, hence n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2 = \frac{X - 3.5}{0.05}

X - 3.5 = -0.1

X = 3.4

Z = 2:

Z = \frac{X - \mu}{s}

2 = \frac{X - 3.5}{0.05}

X - 3.5 = 0.1

X = 3.6

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
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