The conversion of 120 barrels to quarts is 20,160
First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
What the other person said Wo owowowowowo
F(4)=(4-1)+2*4=11...
This seems a bit too easy though, did you mean f(n)=f(n-1)+2n ? In this case :
f(1)=16
f(2)=16+2*2=20
f(3)=20+2*3=26
f(4)=26+2*4=34
The first statement CA || DB , E is midpoint is GIVEN to you. That is the reason that statement can be made. It is GIVEN.
The second statement I would make is that ∠ACE = ∠DBE and ∠CAE = ∠EDB because Alternate interior Angles of parallel line CA || BD. You can also say ∠DEB = ∠CEA due to vertical angles being equal.
The third statement should be that AE = ED because E is the midpoint of AD.
The fourth statement is that the triangles are congruent, this is because ASA . Angle-Side-Angle are equal.
