Answer:
56 g of sucrose is the mass needed
Explanation:
Formula for osmotic pressure → π = M . R . T
8 atm = M . 0.082 L.atm/mol.K . 290 K
8 atm / (0.082 L.atm/mol.K . 290 K) = M → 0.336 mol/L
Let's determine the mass of sucrose that represents 0.336 mol
0.336 mol . 342 g / 1mol = 114.9 g
This is the mass that corresponds to 1L of solution, but we have 0.488 L
Solution density = 1 g/mL → 488 g are contained in 488 mL.
488 mL . 1L / 1000 mL = 0.488 L
Let's make a rule of three:
1L is the volume for 114.9 g of sucrose
In 0.488 L of volume, we need a mass of (0.488L . 114.9 g) 1L = 56 g
