Answer is: the average atomic mass 217.606 amu.
Ar₁= 203.973 amu; the average atomic mass of isotope.
Ar₂ = 205.9745 amu.
Ar₃ = 206.9745 amu.
Ar₄ = 207.9766 amu.
ω₁ = 1.40% = 0.014; mass percentage of isotope.
ω₂ = 24.10% = 0.241.
ω₃ = 22.10% = 0.221.
ω₄ = 57.40% = 0.574.
Ar = Ar₁ · ω₁+ Ar₂ · ω₂ + Ar₃ · ω₃ + Ar₄ · ω₄.
Ar = 203.973 amu · 0.014 + 205.9745 amu · 0.241 + 206.9745 amu · 0.221 + 207.9766 amu · 0.574.
Ar = 2.855 amu + 49.632 amu + 45.741 amu + 119.378 amu.
Ar = 217.606 amu.
But abundance of isotopes is greater than 100%.
It should be lead, with the fourth isotope weighs 207.9766 amu and an abundance of 52.40.
Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.
The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).
Factors specific heat capacity relate to are temperature and strength.
The Speific heat capacity C can be measured as q = mC∆T
Or, C = q/m∆T
where,
C is the specific heat capacity
q is the quantity of heat required
m is the mass
∆T is the change in temperature
As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.
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Answer:
60 g/100 g water
Explanation:
Find 5 °C on the horizontal axis.
Draw a line vertically from that point until you reach the solubility curve for CaCl₂.
Then draw a horizontal line from there to the vertical axis.
The solubility of CaCl₂ is 60 g/100 g water.
