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lianna [129]
3 years ago
14

What are two characteristics of acids

Chemistry
1 answer:
Olenka [21]3 years ago
3 0
<span>Here are some

pH < 7
Sour taste (though you should never use this characteristic to identify an acid in the lab)
Reacts with a metal to form hydrogen gas Increases the H+ concentration in water
Donates H+ ions<span>
Turns blue litmus indicator red</span></span>
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Calcium is an element. What is the smallest particle of calcium that has the same chemical properties of calcium?
Verdich [7]

Answer:

A. An Atom

Explanation:

An atom is the smallest particle of an element, having the same chemical properties as the bulk element.

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2 years ago
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chemical symbol= Cl ( chlorine)

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3 years ago
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What do hydroligists primarly study
serious [3.7K]

Answer:

The study of movement, distribution and quality of water.

Explanation:

They measure the properties of bodied of water, such as the volume of and stream flow.

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3 years ago
Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that
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Answer:

See the answer below, please.

Explanation:

Take as an example a light bulb inside a lamp to illuminate a room. When you plug it in a plug and turn it on, light is generated. More precisely, heat (Joule effect) is produced inside the lamp by its internal filament (conductive material) when it passes through the electrical energy, generated by the friction of the atoms that are inside it when it encounters a resistance.

3 0
3 years ago
The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
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