Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
1.33×10^-6
Step-by-step explanation:
5.32 x 10^-7= 5.32×10^(-5-2)= 5.32×10^-2×10^(-5)
=0.0532×10^-5
(0.0532×10^-5) (2.5 x 10^-5)
0.0532×2.5 × 10^-5
0.133×10^-5= 1.33×10^-1 ×10^-5
1.33×10^-6
Answer:
3 × 5 × 5 × 2 × 2 × 2
Step-by-step explanation:
Make a factor tree.
But let me explain the above to prove it's correct.
3 × 5 = 15
15 × 5 = 75
75 × 2 = 150
150 × 2 = 300
300 × 2 = 600
Therefore 600 as a product of prime factors is: <u>3 × 5 × 5 × 2 × 2 × 2</u>
Answer:
x=6
Step-by-step explanation:
Answer: 1
f(x) = 3x - 4 => f(3) = 3.3 - 4 = 9 - 4 = 5
g(x) = x² => g(2) = 2² = 4
=> f(3) - g(2) = 5 - 4 = 1
Step-by-step explanation:
