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In this problem, we are given that a ball is thrown upward and that it has an initial velocity of 5 m/s. Its path both on Earth and on the moon will be trajectory in nature. This is because while its horizontal velocity is maintained, its vertical velocity increases.
Answer:
v = 1.7 m/s
Explanation:
By applying conservation of energy principle in this situation, we know that:
Loss in Potential Energy of Car = Gain in Kinetic Energy of Car
mgΔh = (1/2)mv²
2gΔh = v²
v = √(2gΔh)
where,
v = velocity of car at top of the loop = ?
g = 9.8 m/s²
Δh = change in height = 45 cm - Diameter of Loop
Δh = 45 cm - 30 cm = 15 cm = 0.15 m
Therefore,
v = √(2)(9.8 m/s²)(0.15 m)
<u>v = 1.7 m/s</u>
Answer:
The the maximum emf is 
Explanation:
Given that,
Magnetic field 
Frequency = 60 Hz
Diameter = 7.8 μm
We need to calculate the maximum emf
Using formula of emf
Where, N = number of turns
B= magnetic field
A = area
Put the value in to the formula
Hence, The the maximum emf is
