Answer:
(a) the average acceleration of the bus while braking is 8.333 m/s
(b) if the bus took twice as long to stop, the acceleration will be half of the value obtained in part a. [¹/₂ (8.333 m/s) = 4.16 s]
Explanation:
Given;
initial velocity of the bus, v = 25 m/s
time of the motion, t = 3 s
(a) the average acceleration of the bus while braking
a = dv/dt
where;
a is the bus acceleration
dv is change in velocity
dt is change in time
a = 25 / 3
a = 8.333 m/s
(b) If the bus took twice as long to stop, the duration = 2 x 3s
a = 25 / (2 x 3s)
a = ¹/₂ x (25 / 3)
a = ¹/₂ (8.333 m/s) = 4.16 s
Thus, if the bus took twice as long to stop, the acceleration will be half of the value obtained in part a.
