|TJ| = sqrt((0 - (-4))^2 + (5 - (-2))^2) = sqrt(4^2 + 7^2) = sqrt(65)
|SE| = sqrt((3 - (-1))^2 + (10 - 3)^2) = sqrt(4^2 + 7^2) = sqrt(65)
|JD| = sqrt((1 - 0)^2 + (-1 - 5)^2) = sqrt(1^2 + (-6)^2) = sqrt(37)
|EK| = sqrt((4 - 3)^2 + (4 - 10)^2) = sqrt(1^2 + (-6)^2) = sqrt(37)
|DT| = sqrt((-4 - 1)^2 + (-2 - (-1))^2) = sqrt((-5)^2 + (-1)^2) = sqrt(26)
|KS| = sqrt((-1 - 4)^2 + (3 - 4)^2) = sqrt((-5)^2 + (-1)^2) = sqrt(26)^2
Since the corresponding sides of the two triangles are equal. the two triangles are congruent by SSS.
Answer: Hello mate!
you know that the equation is (or at least i think this is):
p(t) = 800 + 9t/90 + t^2
You want to know the "rate of change" after 6 hours.
We know that the rate of change is the derivative of P(t) with respect to t; this is
![\frac{dP(t)}{dt} = 9/90 + 2t](https://tex.z-dn.net/?f=%5Cfrac%7BdP%28t%29%7D%7Bdt%7D%20%3D%209%2F90%20%2B%202t)
now we want the rate of change when t = 6, then we replace t by 6 in the derivate equation:
![p(6)' = 0.9 + 2*6 = 12.9](https://tex.z-dn.net/?f=p%286%29%27%20%3D%200.9%20%2B%202%2A6%20%3D%2012.9)
so the rate of change after 6 hours is 12.9
where ![P'(t) = \frac{dP(t)}{dt}](https://tex.z-dn.net/?f=P%27%28t%29%20%3D%20%5Cfrac%7BdP%28t%29%7D%7Bdt%7D)
If the equation is wrong ( because you write P(t) = 800 1 + 9t 90 + t2, and i don really know how to iterprete it) tellme and we can do the derivate again :D
Answer:
Every group of 6 people has at least two uniform 3-person groups.
Step-by-step explanation:
Denote the 6-people by 6-vertices and draw a blue edge between 2-edges. If the two persons representing the vertices are friends. Otherwise, draw a red edge. This gives rise to a colored graph K6, edges arecolored with either blue or red.
There can exist at most 36 mips. so, multicolor triangles can exist at most 36/2 = 18 multicolor triangles.
If there are 20-triangle in graph. Therefore, every graph of 6-people has at least two uniform 3-person groups.
<em>Answer:</em>
<em>this is what I found I hope it helps</em>
<em>3 acute angles
</em>
<em>2 acute angles, 1 right angle
</em>
<em>2 acute angles, 1 obtuse angle</em>
<em />