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Elis [28]
3 years ago
6

Help me please this is for physics

Physics
1 answer:
Yuri [45]3 years ago
3 0
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

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Four round objects of equal mass and radius roll without slipping along a horizontal surface that then bends upward and backward
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A

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inertia Equation for All Object is k m R²

inertia Equation of Hollow Cylinder I = m R²

inertia Equation of Solid Cylinder I = ½ m R²

inertia Equation of Hollow Sphere I = ⅔ m R²

inertia Equation of Solid Sphere I = 2/5 m R²

to find the speed needed we can use Mechanical Energy (ME). or Total Energy.

ME = Translation Kinetic Energy + Rotation Kinetic Energi

ME = ½ m v² + ½ I w²

ME = ½ m v² (1 + k)

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sinnce all objects have the same mass, we can figure that v² is proportionally with 1/(1+k)

v²(hc) = 1/(1+1) = ½ = 0.5

v = 0.707

v²(sc) = 1/(1+½) = 2/3 = 0.67

v = 0.818

v²(hs) = 1/(1+⅔) = 3/5 = 0.6

v = 0.744

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v = 0.842

these is the ratio of speed they produce in the end of the arc with initial speed = 0 m/s

so, if we must give speed to the object so that it can reach the end of the arc, the fastest speed is given to hollow cylinder and the slowest speed is given to Solid Sphere

Then the answer is

HC, HS, SC, SS

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