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A particular circuit toolbox contains only 80 Ω resistors and switches, which can be open or closed. Construct a circuit, fillin

Strike441 [17]

Answer:

Here we need to make parallel connection of two 80 ohm resistors to achieve 40 ohm net resistance.

Explanation:

As we know that the resistances in series add up directly and here we are given with only the resistors of 80 Ω.

So when we connect two resistors of 80 ohm in parallel we get the resultant of 40 ohm.

Mathematically:

$\frac{1}{R_p} =\frac{1}{R} +\frac{1}{R}$

$\frac{1}{40} =\frac{1}{R} +\frac{1}{R}$

$\frac{1}{40} =\frac{2}{R}$

$R=80\Omega$ gives us the only combination of two resistors in parallel.

3 0

2 years ago

Which layer of the earth can be seen from the open hole

umka21 [38]

Answer:

the inner core

Explanation:

6 0

2 years ago

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Convert 7.93 lbs into grams. Hint: 1 kg = 2.2 lbs

Alekssandra [29.7K]

Answer:

7.93 lbs is equal to 3596.987 grams.

Explanation:

The weight in grams is equal to the pounds multiplied by 453.59237.

So... you would multiply 7.93 by 453.59237.

7.93 x 453.59237 = 3596.987

Hope that helped!

6 0

2 years ago

Read 2 more answers

in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's

GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

Where

I₁ = Intensity at distance 1 (W/m²)
I₂ = Intensity at distance 2 (W/m²)
d₁ = distance 1 from a light source (m)
d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

$\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}$

$\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}$

$I_{2} = \frac{200} {36}$

I₂ = 5.55 W/m²

Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².

Learn more about intensity of light here:

brainly.com/question/13155277

#SPJ4

3 0

8 months ago

A stable air mass is most likely to have which characteristic? 1. turbulent air 2. poor surface visibility 3. showery precipitat

Ne4ueva [31]

A stable air mass is most likely to have POOR SURFACE VISIBILITY.
Stable air mass refers to those air mass that have marked stability in their lower layers. The characteristics of stable air mass include the following: cloud cover, smooth air, uninterrupted precipitation and low visibility.<span />

3 0

3 years ago

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