Answer:
Option (A)
Explanation:
A flowchart can be described as a representation of a process or an algorithm in a sequential manner (stepwise) in the form of diagrams. These steps are made of symbols that are connected to one another with the help of arrows. These arrows are used to show the direction of the process.
There are mainly four symbols that are used to describe a flow chart, which includes-
- Oval or Pill Shape- This type of symbol is used to depict the start or the end of a process.
- Rectangle Shape- This type of symbols is used to describe the process
.
- Diamond Shape- This type of symbol is used to represent decision
s.
- Parallelogram- This type of symbol is used for the representation of an input or an output.
Thus, the correct answer is option (A).
Object 2 has more kinetic energy
Explanation:
The kinetic energy of an object is the energy possessed by the object due to its motion, and it is given by
where
m is the mass of the object
v is its speed
In this problem, for object 1:
m = 2 kg
v = 2 m/s
So its kinetic energy is
For object 2,
m = 4 kg
v = 3 m/s
So its kinetic energy is
Therefore, object 2 has more kinetic energy.
Learn more about kinetic energy:
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Answer:
2682
Explanation:
Work done is given by :
Work = Force x distance
= mg x d
So, work done in lifting the box of 23 kg up to my waist of 1 m high is :
W = mg x d
= 23 x 9.18 x 1
= 211.14
Now work done carrying the box horizontally 6 meters across the room is
W = mg x d
= 23 x 9.18 x 6
= 1266.84
Work done in placing the box on the shelf that is 5.7 m above the ground is
W = mg x d
= 23 x 9.18 x 5.7
= 1203.49
So the total work done is = 211.14 + 1266.84 + 1203.49
= 2681.47
= 2682 (rounding off)
<span>If Paul and Ivan has a speed of 5 meters/second in which their combined mass is 50 kg. To increase the bike's kinetic energy, Paul must increase its speed as well. Increasing his speed allows an increase in momentum of them running the bike. The kinetic energy equation is KE = 0.5mv</span>² where m is mass, v is speed and KE is kinetic energy.
The answer is d.heuristic
