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4 years ago

Which action is an example of poor sportsmanship

1 answer:

6 0

Yelling rude comments to the winning team or claiming the winning team cheated is one example. Another example could be something like crying about loosing and throwing a hissy fit over not winning

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Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocit

natima [27]

Answer:

a 18

Explanation:

6 0

3 years ago

Potassium is a crucial element for the healthy operation of the human

Dovator [93]

The second one if it’s on edge

8 0

3 years ago

Find the current that flows in a silicon bar of 10-μm length having a 5-μm × 4-μm cross-section and having free-electron and hol

alexdok [17]

Explanation :

It is given that,

Length of silicon bar, $l=10\mu m= 0.001\ cm$

Free electron density, $n_e=104\ cm^3$

Hole density, $n_h=1016\ cm^3$

$\mu_n=1200\ cm^2/Vs$

$\mu_p=500\ cm^2/Vs$

The total current flowing in bar is the sum of drift current due to hole and the electrons.

$J=J_e+J_h$

$J=nqE\mu_n+pqE\mu_p$

where, n and p are electron and hole densities.

$J=Eq[n\mu_n+p\mu_p]$

we know that $E=\dfrac{V}{l}$

So, $J=\dfrac{V}{l}q[n\mu_n+p\mu_p]$

$J=\dfrac{1.6\times 10^{-19}\ C}{0.001\ V}[104\ cm^{-3}\times 1200\ cm^2/V\ s+1016\ cm^{-3}\times 500\ cm^2/V\ s]$

$J=1012480\times 10^{-16}\ A/m^2$

$J=1.01\times 10^{-9}\ A/m^2$

Current, $I=JA$

A is the area of bar, $A= 20\mu m=0.002\ cm$

So, $I=1.01\times 10^{-9}\ A/m^2\times 0.002\ m^2$

Current, $I=2.02\times 10^{-12}\ A$

<em>So, the current flowing in silicon bar is </em> $I=2.02\times 10^{-12}\ A$ .

7 0

4 years ago

A geologist finds that a Moon rock whose mass is 8.94 kg has an apparent mass of 6.18 kg when submerged in water. What is the de

Grace [21]

Density of rock = 3.23 Kg/m^3

Given:

mass of Moon rock = 8.94 kg

apparent mass of Moon rock = 6.18 kg

To Find:

density of the rock

Solution: It is a universal fact that mass of an object remains constant whether measured on earth or on moon.

Mass of rock on moon/earth = 8.94 kg

When the block is immersed in water then;

Loss in weight = weight of water displaced

Loss in weight = 8.94 - 6.18 = 2.76 kg

As we know that water has a density of 1g/cm^3 (1000kg/m^3)

Volume of water = volume of the rock = Mass/density = 2.76 kg

density of rock mass/volume = 8.94/2.76 = 3.23 Kg/m^3

Density of rock = 3.23 Kg/m^3

Learn more about Density here:

brainly.com/question/1354972

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4 0

2 years ago

The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a

sertanlavr [38]

Answer:

Electric field, E = $6.36\times 10^{6}\ V/m$

Explanation:

Given that,

The potential difference across the membrane, $\Delta V=0.063\ V$

The thickness of the membrane is, $\Delta x=9.9\times 10^{-9}\ m$

We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

$E=\dfrac{-\Delta V}{\Delta x}\\\\E=\dfrac{0.063\ V}{9.9\times 10^{-9}\ m}\\\\E=6.36\times 10^{6}\ V/m$

So, the magnitude of the electric field in the membrane is $6.36\times 10^{6}\ V/m$ .

7 0

4 years ago