Assuming that 10% is the probability of a switch being defective (since left-handedness has nothing to do with the problem):
For a binomial distribution, probability(r out of n) = (nCr) (p)^r (q)^(1-r)
p = 10% = 0.1, q = 1 - p = 0.9
r = 2 switches, n = total of 12 switches
probability = (12C2) (0.1)^2 (0.9)^(12-2)
probability = 66(0.1)^2 (0.9)^10
probability = 0.23
Answer:A
Step-by-step explanation:
I just took the test
All you have to do is divide
500 divided by 10 equals 50
so 50 cars went on the picnic trip
Answer:
m∠TSP = 53°
Step-by-step explanation:
m∠RSU and m∠TSP are vertical angles
