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Andre45 [30]
2 years ago
13

What is the Probability A high school band has 8 freshmen, 12 sophomores, 16 juniors, and 14 seniors? If a student is selected a

t random, find the probability that the student is a senior.
Mathematics
1 answer:
pentagon [3]2 years ago
6 0
.28 or 28% chance the randomly selected student is a senior. There are 50 total students in the band, and 14 seniors, so the probability that a senior is randomly selected is 14/50 or .28
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Can someone pls help?
GenaCL600 [577]

Answer: 2

Step-by-step explanation:

Because if u divide 12÷6=2 2×6=12

3 0
3 years ago
Read 2 more answers
What’s the answer to this question?
lutik1710 [3]

Answer: B

Step-by-step explanation:

(f+g)(x) means f(x)+g(x). It is saying to add f(x) and g(x). Since we were given f(x) and g(x), we can directly add them together.

(f+g)(x)=4x+2+x²-6                        [combine like terms]

(f+g)(x)=x²+4x-4

Now that we have found (f+g)(x)=x²+4x-4, the answer is B.

6 0
3 years ago
What is the square root of 64? I don't understand.<br> Will give brainliest
inessss [21]
Square root is the number that when multiplied when itself give the number you are looking for if that makes any sense.
8 is the square root of 64 because 8x8 = 64
7 0
3 years ago
Read 2 more answers
Part B if u want part A too
Anna11 [10]
I dont get the question

6 0
3 years ago
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
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