Answer:
2.1056L or 2105.6mL
Explanation:
We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:
Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol
Mass of Na2CO3 = 10g
Mole of Na2CO3 =.?
Mole = mass /molar mass
Mole of Na2CO3 = 10/106
Mole of Na2CO3 = 0.094 mole
Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:
Na2CO3 + 2HCl —> 2NaCl + H2O + CO2
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CO2.
Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.
Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:
1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.
Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L
Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL
option of d is the write answer
The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.
1g = 1000mg
The mass of 1 mole of Kr = 83.80g Kr
Convert mg Kr to g Kr.
398mg Kr x (1g/1000mg) = 0.398g Kr
Convert g Kr to mol Kr.
0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
Answer:
This is required answer.
Explanation:
Given that,
Thermal energy chemical change lab report
We know that,
Thermal energy :
When we rise a temperature of any substance then the molecules of substance moves fastly then the heat produced. It is called thermal energy.
Chemical change in the thermal energy :
When we heat a substance then the thermal energy increases and the molecules of substance moves fastly. That means the chemical bonds are break in reactants due to energy.
In products, The new chemical bonds are create due to energy.
For example ; The coal is burned then produced heats water and change it into steam.
Hence, This is required answer.
Answer:
A ,B- false
C,D- true
Explanation:
Dipole forces always lead to stronger attraction and boiling points than dispersion forces. When linear molecules are involved, they often posses greater dipole forces and higher boiling points. Linear alkanes posses higher boiling points than branched alkanes.
