If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
V-10=-3
add 10 by both sides (opposite of -10)
v= 7
Answer:
Option D
Step-by-step explanation:
A type I error occurs when you reject the null hypothesis when it is actually true.
The null hypothesis in this case is minimum breaking strength is less than or equal to 0.5.
A type one error would be allowing the production process to continue when the true breaking strength is below specifications.
Answer:
{x,y}={ 5/9,0}
Step-by-step explanation:
9x - 2y = 5
y = 0
9x - 2•() = 5
9x = 5
x = 5/9
By now we know this much :
x = 5/9
y = 0
⇒{x,y} = {5/9,0}
