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3 years ago

A lake that is protected from receiving the runoff from a cultivated field is likely to remain a healthy ecosystem. t or f

2 answers:

7 0

This answer is false because if you have a field that runs off into a lake all of the manure and chemicals from that field gets into the soil and in return runs off into the water.

Tanya [424]3 years ago

7 0

The answer to your question is true.

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How can an electron cloud be compared with a spinning airplane propeller? Both represent objects that move in a circular motion

adelina 88 [10]

The answer is that exact locations within either cannot be determined at any given moment in time.

An electron cloud be compared with a spinning airplane propeller in the manner that in both exact location within either cannot be determined at any given moment in time.

In both electron cloud as well as spinning airplane propeller, there is a probability of finding either but exact location can not be determined.

6 0

3 years ago

Read 2 more answers

A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg

Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a $\sqrt{3}$ /4

Given

a = 360 pm

Therefore

r = r = radius = 360 $\sqrt{3}$ /4= 155.88 pm

156 pm

3 0

3 years ago

Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq

nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of $CaC_2$ = $2.54\ g$

Molar mass of $CaC_2$ = 64.099 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{2.54\ g}{64.099\ g/mol}$

$Moles_{CaC_2}= 0.0396\ mol$

According to the given reaction:-

$CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}$

1 mole of $CaC_2$ on reaction forms 1 mole of $C_2H_2$

0.0396 mole of $CaC_2$ on reaction forms 0.0396 mole of $C_2H_2$

Moles of $C_2H_2$ = 0.0396 moles

Considering ideal gas equation as:-

$PV=nRT$

where,

P = pressure of the gas = 742 mmHg

V = Volume of the gas = ?

T = Temperature of the gas = $26^oC=[26+273]K=299K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

$742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L$

1.0 L of acetylene can be produced from 2.54 g $CaC_2$ .

4 0

3 years ago

How many O2 molecules can be made with the oxygen from 492 g of sodium phosphate?

serg [7]

To answer this question, you need to change the sodium phosphate unit into mol and doing the reaction. Sodium phosphate or Na3PO4 molecular weight is 163.94 or 164 rounded up. Then the amount should be: 492g/ (164g/mol)= 3 mol

For every 1 mol of Na3PO4 there are 4 mol of oxygen element. To made 1 mol of O2 molecule, you will need 2 mol oxygen element. Then the amount of oxygen should be: 4/2 * 3 mol= 6 mol * 6.02 * 10^23= 36.12 * 10*23= 3.61 * 10^24

7 0

3 years ago

Read 2 more answers

How would you figure the number of protons or electrons in an atom

TiliK225 [7]

The number of protons in an atom can be determined by the element's atomic number, and the number of electrons can be determined by subtracting by atomic mass by the atomic number.

8 0

3 years ago