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Bezzdna [24]
3 years ago
12

Nap ate 2/5 of the pizza Rowan ate 2/3 of the pizza that was left how much of the pizza did Rowan eat

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

Rowan ate \frac{2}{5} of the pizza

Step-by-step explanation:

Nap ate 2/5 of the pizza Rowan ate 2/3 of the pizza that was left how much of the pizza did Rowan eat?

Nap: \frac{2}{5} can be rewritten as \frac{6}{15}

Rowan: \frac{2}{3} can be rewritten as \frac{10}{15}

After Nap ate 2/5 of the pizza, there is 3/5 pizza left.

\frac{3}{5} can be rewritten as \frac{9}{15}

 

\frac{9}{15}*\frac{10}{15} = \frac{2}{5}

\frac{9}{15}*\frac{10}{15}=\frac{3}{5}*\frac{2}{3}=\frac{1}{5}*\frac{2}{1} =\frac{2}{5}

Rowan ate \frac{2}{5} of the pizza

Hope this helps!

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Which of the following expressions has a value of 26.48?
gulaghasi [49]

Answer:

26.48=\dfrac{662}{25}

Step-by-step explanation:

The given expression is 26.48. We need to write the equivalent expression for it. There are two numbers after decimal. It means that we can divide 2648 by 100 i.e.

26.48=\dfrac{2648}{100}

We know that, 2648 = 662 × 4 and 100 = 25 × 4

\dfrac{2648}{100}=\dfrac{662\times 4}{25\times 4}\\\\=\dfrac{662}{25}

Hence, 26.48=\dfrac{662}{25} is the equivalent expression.

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4 years ago
There are 5 green balls, 2 orange balls, 4 purple balls, and 1 pink ball in a bucket. You pick 1 ball from
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A.
Sophie [7]

Answer:

B.

Step-by-step explanation:

I graphed it but you could also use the y intercept to determine which function matches the graph

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4 0
3 years ago
Of all sixth graders, 70% sent a text message yesterday. Ten trials of a simulation are conducted and the data are recorded belo
Effectus [21]

Answer:

80%

Step-by-step explanation:

According to the given data, the numbers 0 through 6 represent students who sent a text yesterday while the numbers 7 through 9 represent students who did not send a text yesterday.

Based on this key, we will calculate the number of students who sent the text yesterday and the number of students who did not sent the text yesterday.

The given data is: 62072, 34570, 80983, 04292, 83150, 36330, 96268, 14077, 77985, 13511

For each group we will identify how many students sent the text and how many students did not. According to the key, a number from 0 to 6 will be counted as a student who sent the text and a number from 7 to 9 will be counted as a student who did not send the text. Students who did not sent the text are made bold in the groups below.

62072:  4 students sent the text, 1 did not

34570:  4 students sent the text, 1 did not

80983:  2 students sent the text, 3 did not

04292:  4 students sent the text, 1 did not

83150:   4 students sent the text, 1 did not

36330:  All 5 students sent the text

96268:  3 students sent the text, 2 did not

14077:   3 students sent the text, 2 did not

77985:  1 student sent the text, 4 did not

13511:    All 5 students sent the text

We need to find the probability that 3 or more of a group of 5 students randomly selected will send a text today.

From the given groups, the number of groups where 3 or more students sent a text = 8

This represents our number of favorable or desired outcomes.

Total number of possible outcomes is the total number of groups = 10

Since, probability is defined as the ratio of number of favorable outcomes to total number of outcomes, based on the simulated data  the probability that 3 or more of a group of 5 students randomly selected will send a text today will be = \frac{8}{10}=0.80=80\%

Thus, based on the simulated data there is 80% probability that 3 or more of a group of 5 students randomly selected will send a text today

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The equation is y=3x+8
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