Answer:

Step-by-step explanation:
Given that f(x) is a polynomial function.
This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.
Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)
i.e. If
is a root, then
is also a root.
(Because this only when multiplied will make coefficients rational)
So the factors of f(x) should be atleast

There can be other factors also but this is compulsory

⇒ x - 6 = 2x + 26
⇒ x = -32
⇒ This Equation has One Solution
So, It matches with A in Column B
2. 2 + 6x - 7 = 8 + 2x - 10 + 4x
⇒ 6x - 5 = 6x - 2
As, They are Equations of Parallel Lines. They never meet each other.
⇒ This Equation has No Solution
⇒ So, It matches with B in Column B
3. 15x + 25 = 15x + 10
As, They are Equations of Parallel Lines. They never meet each other.
⇒ This Equation has No Solution
⇒ So, It matches with B in Column B
4. 16 + 8x = 4(2x + 4)
⇒ 16 + 8x = 16 + 8x
As, Both Equations are Same. They Represent the Same Line.
⇒ This Equation has Infinite Number of Solutions
⇒ So, It matches with C in Column B
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Simple...
you have:

Dividing-->>
0.23076923
But, remember, you're rounding to the nearest hundreth...
0.23Thus, your answer.