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yulyashka [42]
2 years ago
15

What is 1 2/3 divided by 1 5/6

Mathematics
2 answers:
Vilka [71]2 years ago
8 0
Ve thirds Conversion a mixed number 1 5/ 6 to a improper fraction: 1 5/6 = 1 5/ 6 = 1 · 6 + 5/ 6 = 6 + 5/ 6 = 11/ 6 To find a new numerator: a) Multiply the whole number 1 by the denominator 6. Whole number 1 equally 1 * 6/ 6 = 6/ 6 b) Add the answer from previous step 6 to the numerator 5. New numerator is 6 + 5 = 11 c) Write a previous answer (new numerator 11) over the denominator 6. One and five sixths is eleven sixths Divide: 5/ 3 : 11/ 6 = 5/ 3 · 6/ 11 = 5 · 6/ 3 · 11 = 30/ 33 = 3 · 10 / 3 · 11 = 10/ 11 Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 11/ 6 is 6/ 11 ) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the following intermediate step, cancel by a common factor of 3 gives 10/ 11 . In other words - five thirds divided by eleven sixths = ten elevenths.
Lemur [1.5K]2 years ago
5 0

Answer:

10/11

Step-by-step explanation:

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If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)
Rasek [7]

Answer:

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If -2+\sqrt{8} is a root, then -2-\sqrt{8} is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

There can be other factors also but this is compulsory

7 0
2 years ago
I need to show my work & have the correct answer, may someone help , I'm really bad at math
Harlamova29_29 [7]
See picture for answers

4 0
2 years ago
PLEEAASE HELP MEEEEEE
Gre4nikov [31]

\mathsf{1.\; \frac{x - 6}{2} = x + 13}

⇒ x - 6 = 2x + 26

⇒ x = -32

⇒ This Equation has One Solution

So, It matches with A in Column B

2. 2 + 6x - 7 = 8 + 2x - 10 + 4x

⇒ 6x - 5 = 6x - 2

As, They are Equations of Parallel Lines. They never meet each other.

⇒ This Equation has No Solution

⇒ So, It matches with B in Column B

3. 15x + 25 = 15x + 10

As, They are Equations of Parallel Lines. They never meet each other.

⇒ This Equation has No Solution

⇒ So, It matches with B in Column B

4. 16 + 8x = 4(2x + 4)

⇒ 16 + 8x = 16 + 8x

As, Both Equations are Same. They Represent the Same Line.

⇒ This Equation has Infinite Number of Solutions

⇒ So, It matches with C in Column B

8 0
3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
3/13 as a decmal ronded to the nearest hundeth
Illusion [34]
Simple...

you have: \frac{3}{13}

Dividing-->>

0.23076923

But, remember, you're rounding to the nearest hundreth...

0.23

Thus, your answer.
8 0
3 years ago
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