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vivado [14]
3 years ago
13

Does substitution reactions cause haloalkanes?

Chemistry
1 answer:
ivanzaharov [21]3 years ago
6 0

Answer:

No, that sort of reaction do not form named compounds.

Explanation:

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A NaOH(aq) solution with a pH value of 13 is used to determine the molarity of a HCl(aq) solution. A 10.0-mL sample of the HCl(a
erica [24]

Answer:

pH of the H⁺(aq) is 0

Explanation:

It is possible to know the  concentration of a HCl(aq) solution by titration with a solution of NaOH(aq) with known concentration. The reaction is:

HCl(aq) +  NaOH(aq) → H₂O(l) + NaCl(aq)

The added moles of NaOH are equal to moles of HCl and as you know volume of HCl added you will obtain concentration of HCl.

Now, a solution of H⁺(aq) with a concentration 10 times greater than original NaOH(aq) solution -0.100M-, has a concentration of 1.00M H⁺(aq), the pH of this solution is:

pH = -log (1.00M H⁺(aq) = 0

That means <em>pH of the H⁺(aq) is 0</em>

5 0
3 years ago
Choose the correct answer from the options given.
Pavel [41]

Answer: 1 part is sulfuric acid is a catalyst

2 part is vanadium (V) oxide is a catalyst

Explanation:

4 0
3 years ago
Why do we use scientific notation or scientific exponential numbers in math calculations?
seraphim [82]
I believe the answer is: in order not to write very big or very small number values
6 0
3 years ago
1
fredd [130]
Answer: Combustion changes the potential chemical energy into kinetic energy in the form of heat. For combustion an organic wood combines with oxygen already in the air and undergoes a chemical reaction that gives off carbon dioxide,water,and energy in the form of heat and light.
8 0
3 years ago
A chemist adds 0.60L of a 0.20/molL sodium thiosulfate Na2S2O3 solution to a reaction flask. Calculate the millimoles of sodium
Serggg [28]

Answer:

1.2×10² mmole of Na₂S₂O₃

Explanation:

From the question given above, the following data were obtained:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the number of mole of Na₂S₂O₃ in the solution as illustrated below:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity = mole /Volume

0.2 = Mole of Na₂S₂O₃ / 0.6

Cross multiply

Mole of Na₂S₂O₃ = 0.2 × 0.6

Mole of Na₂S₂O₃ = 0.12 mole

Finally, we shall convert 0.12 mole to millimole (mmol). This can be obtained as follow:

1 mole = 1000 mmol

Therefore,

0.12 mole = 0.12 mole × 1000 mmol / 1 mole

0.12 mole = 120 = 1.2×10² mmole

Thus, the chemist added 1.2×10² mmole of Na₂S₂O₃

7 0
3 years ago
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