Answer: a) 
b) 
Explanation:
a) If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 15.8g
Mass of S= 84.2 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of S=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = 
For S =
The ratio of C : S = 1:2
Hence the empirical formula is
b) Mass of C= 40 g
Mass of H= 6.7 g
Mass of O = 53.3 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = 
For H = 
For O =
The ratio of C : H: O= 1 :2: 1
Hence the empirical formula is
The emission of a beta particle has the effect of : C. No change in mass
basically, beta particle has a very very little mass compared to the proton and neutrons, so little to the point that it never considered as a change in mass. But it does decreases the charge of atom
hope this helps
Answer:
0.1077 grams
Explanation:
First we will employ the ideal gas law to determine the number of moles of nitrogen gas.
PV=nRT
P=2 atm
V=20L
R=0.08206*L*atm*mol^-1*K^-1
T=323.15 K
Thus, 2atm*20L=n*0.08206*L*atm*mol^-1*K^-1*323.15K
K, atm, and L cancels out. Thus n=2*20mol/0.08206*323.15=1.5 moles
Lastly, we must convert the number of moles to grams. This can be done by dividing the number of moles by the molar mass of nitrogen gas, which is 14 grams.
1.5/14=0.1077 grams
Answer:
H2O
Explanation:
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