1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Travka [436]
3 years ago
13

How the ph values can be used to compare the strength of hydrochloric acid and ethanoic acid?

Chemistry
1 answer:
devlian [24]3 years ago
3 0
An aqueous solution of hydrozen chloride: Strongly​ corrosive acids
A colouriess punpent liquid widely used in manufacturing plastic and pharmaceutical
You might be interested in
30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

4 0
3 years ago
Calculate the molecular formula of a compound with the empirical formula C5H11 and a molar mass of 142.32 grams/mole
MA_775_DIABLO [31]
Relative formula mass C₅H₁₁ = 71

Now divide the molar mass by the RFM = 142.32 / 71 = 2

Now C₍₅ₓ₂₎H₍₁₁ₓ₂) = C₁₀H₂₂

Hope that helps
6 0
3 years ago
What mass of KNO, will dissolve in 100 g of water at 100°C?
Sphinxa [80]

Answer:

About 170-180 grams of potassium nitrate are completely dissolved in 100 g.

Explanation:

Hello!

In this case, according to the reported solubility data for potassium nitrate at different temperatures on the attached picture, it is possible to bear out that about 170-180 grams of potassium nitrate are completely dissolved in 100 g; considering that the solubility is the maximum amount of a solute that can be dissolved in a solvent, in this case water.

Best regards!

3 0
3 years ago
INFORMATION FOR MY LAST QUESTION THIS IS PART A OF THE QUESTION
Anika [276]

Answer:

The print is so little i cant read it. :( Sorry!

Explanation:

4 0
3 years ago
Which example illustrates the transfer of energy through RADIATION?
iragen [17]
I think it is feeling warm air while standing in front of the blower from a heating system.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Other questions:
  • Horsetail are helpful for treating
    15·1 answer
  • List 10 examples of substances that are beneficial in small quantities but poisonous in large doses
    10·2 answers
  • Silicon has three naturally occurring isotopes. Silicon-28 has a mass of 27.98 and a relative abundance of 92.23%. Silicon-29 ha
    7·2 answers
  • What are some physical properties of metals?
    15·2 answers
  • Calculate the concentration of OH- in a solution that contains 3.9 x 10-4 M H3O+ at 25°C. Identify the solution as acidic, basic
    8·1 answer
  • List the following types of electromagnetic radiation in order of increasing wavelength.
    9·1 answer
  • Barium reacts with a polyatomic ion to form a compound with the general formula Ba3(X)2. What would be the most likely formula f
    8·2 answers
  • What properties do atoms of the same element share? Select all that apply.
    10·2 answers
  • I NEED HELP WITH BOTH QUESTIONS PLZZ!!!!!!!!
    5·2 answers
  • 2 upper N upper O subscript 2 (g) right arrow 2 upper N upper o (g) plus upper O subscript 2 (g). Second: 2 upper N upper O (g)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!