To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:
mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
Answer:
0.080 mol
Explanation:
M(HCl) = (1.0 +35.5) g/mol = 36.5 g/mol
2.9g*1mol/36.5 g = 0.0795 mol HCl
Ca(OH)2 + 2HCl ---> CaCl2 + 2H2O
from reaction 2 mol 2 mol
given 0.0795 mol x mol
x = 0.0795 mol ≈0.080 mol
The amount of electrons is based on the proton number
