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Eddi Din [679]
2 years ago
7

Explain how the bonding models for sodium metal differ from the bonding model for sodium chloride

Chemistry
1 answer:
Scrat [10]2 years ago
4 0

Answer:

See below.

Explanation:

Different types of bond models, different interactions of particles in the inner structures.

For sodium metal,

The basic particles, the unit, is metal sodium. So the interaction is originated from metal and metal. We call this interaction, metal, atom-atom interaction.

For sodium chloride,

The basic particles, is 2 different ionic particles, positive particle (sodium, Na+), and negative particle (chloride, Cl-). We call this interaction, ionic-ionic interaction.

So, different interactions, different structures, thus, finally, different binding models.

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Answer: The molar enthalpy change is 73.04 kJ/mol

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HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

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q=150.0\times 4.184\times 4.83

q=3031.3J

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Thus molar enthalpy change is 73.04 kJ/mol

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