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Leviafan [203]
3 years ago
9

A certain substance X has a normal boiling point of 124.2 °C and a molal boiling point elevation constant K,-06-0C-kg-mol ·A sol

ution is prepared by dissolving some urea ((N112)CO) in 650. g ofl. This solution boils at 124.7 oC, Calculate the mass of urea that was dissolved. Be sure your answer has the correct number of significant digits. 31.48 g
Chemistry
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

32 g

Explanation:

The increase in the boiling point of X can be calculated using the following expression.

ΔT = Kb × b

where,

ΔT: increase in the boiling point

Kb: molal boiling point constant (0.62 °C.kg/mol) (I looked it on the web)

b: molality of the solute

ΔT = Kb × b

(124.7°C - 124.2°C) = (0.62 °C.kg/mol) × b

b = 0.81 mol/kg

The mass of X is 650 g (0.650 kg). Then, the moles of urea (solute) are:

\frac{0.81molUrea}{1kgX} .0.650kgX=0.53molUrea

The molar mass of urea is 60.06 g/mol. The mass of urea is:

0.53mol.\frac{60.06g}{mol} =32g

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A dunk tank hold 30,533 moles of water? How many grams of water are in the tank?
liubo4ka [24]

The mass of water in the tank, given the data from the question is 549594 g

<h3> Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mass of water in the tank</h3>

From the question given above, the following data were obtained:

  • Mole of water = 30533 moles
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  • Mass of water = ?

The mass of the water can be obtained as follow:

Mass = mole × molar mass

Mass of water = 30533 × 18

Mass of water = 549594 g

Learn more about mole:

brainly.com/question/13314627

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