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antoniya [11.8K]
3 years ago
12

Calculate the oxidation number of the iodine (I) in each compound: HIO4 = I2 = NaI = HIO3 =

Chemistry
2 answers:
Makovka662 [10]3 years ago
8 0
1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.

2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.

3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.

4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
Tems11 [23]3 years ago
6 0

Answer:

the answer has the plus sign in it...

+7

0

-1

+5

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Explanation:

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From the equation, the amount of ethanol produced is twice the amount of yeast present, or the same amount of carbon dioxide produced. Do note that amount refers to the number of moles here.

Mole= Mass ÷Mr

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<u>Method 1: using the </u><u>mass of glucose</u>

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Mass of ethanol formed

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Thus, 102 g of ethanol are formed.

Additional:

For a similar question on mass and mole ratio, do check out the following!

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