QUESTION 2. What is the molar mass of a gas that takes three times longer to effuse than helium?
1 answer:
Molecular weight of x=36g/mol
(According to graham's law of effusion or diffusion, the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.
RateB
RateA
=
(
molarmassA
molarmassB
)
Let Rate of unknown gas = x; Rate of Helium = 3x; mass of unknown gas = y
mass of He = 4.
x
3x
=
(
4
y
(
4
y
)
=3
squaring on both sides
(
4
y
)
=9
∴y=4×9=36u)
(According to graham's law of effusion or diffusion, the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.
RateB
RateA
=
(
molarmassA
molarmassB
)
Let Rate of unknown gas = x; Rate of Helium = 3x; mass of unknown gas = y
mass of He = 4.
x
3x
=
(
4
y
(
4
y
)
=3
squaring on both sides
(
4
y
)
=9
∴y=4×9=36u)
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