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lilavasa [31]
3 years ago
5

Atoms of the LEAST reactive elements tend to have A. one or seven valence electrons. B. eight valence electrons. C. four or five

valence electrons. D. no valence electrons
Chemistry
2 answers:
Tomtit [17]3 years ago
3 0
B. eight valence electrons.
nasty-shy [4]3 years ago
3 0

Answer: Option (B) is the correct answer.

Explanation:

When an atom's octet or shell is filled then the atom becomes stable. Therefore, the atom will be very less reactive as it does not need more electrons to fill its shell.

For example, neon has atomic number 10 and electron distribution in its shells is 2, 8. As there are 8 electrons in its valence shell this means that it has attained stability according to the octet rule. Hence, it will be least reactive.

Thus, we can conclude that atoms of the LEAST reactive elements tend to have eight valence electrons.

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MaRussiya [10]
Atomic mass of helium is 4.002642g/mol 
(542000g)/(4.002642g/mol)*6.02*10^23 = 8.15*10^28 atoms
3 0
3 years ago
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Which molecule transports oxygen in red blood cells? (1 point)
Afina-wow [57]
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6 0
3 years ago
4. a compound called pyrene has the empirical formula c8h5. when 4.04 g of pyrene is dissolved in 10.00 g of benzene, the boilin
e-lub [12.9K]

The molecular mass of pyrene is 204.4 g/mol.

From;

ΔT = Kb m i

Where;

  • ΔT = boiling point elevation
  • Kb = boiling point constant
  • m = molality
  • i = Van't Hoff factor

Since the compound is molecular; i = 1

The number of moles of pyrene = 4.04 g/MM

Where; MM = molar mass of pyrene

molality = number of moles of pyrene/mass of solvent in Kg

The mass of solvent = 10 g or 0.01 Kg

molality =  4.04 g/MM/0.01

ΔT = Boiling point of solution - Boiling point of pure solvent

ΔT = 85.1°C - 80.1°C

ΔT = 5°C

5 = 2.53 × 4.04 g/MM/0.01 × 1

5 = 10.22 × 1/0.01 MM

0.05MM = 10.22

MM= 10.22/0.05

MM= 204.4 g/mol

Learn more: brainly.com/question/2292439

3 0
2 years ago
According to the law of conservation of mass, the total mass of the reactants is
yarga [219]

Answer:

is equal to the total number of products

Explanation:

3 0
3 years ago
Sulfur has an atomic mass of 32 u and Avogadro's number is 6 × 1023 formula units/mole. The number of sulfur atoms in 1 g of sul
Vikki [24]

Answer:

The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6\times 10^{23}

Given atomic mass of sulfur = 32 u

Which means that:-

32 g of sulfur contains 6\times 10^{23} of atoms

Also,

1 g of sulfur contains \frac {6\times 10^{23}}{32} of atoms

<u>So, The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms</u>

6 0
3 years ago
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