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2 years ago

Can someone please give me the (Answers) to this? ... please ... I need help….

Mathematics

1 answer:

Blizzard [7]2 years ago

6 0

Step-by-step explanation:

hope it's helpful please let me know

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Help pls! What is the quotient 3/4 and 5/6 3/4 9/10 1 1/9 4 1/2

valkas [14]

Answer:

9/10

Step-by-step explanation:

To divide by 5/6, invert 5/6, obtaining 6/5, and then multiply:

3 6

------ * ----- = 18/20 = 9/10 (same as the 2nd possible answer)

4 5

7 0

3 years ago

Please I need Help!!! Solve this equation by factoring by grouping x^2-4x=12. All work must be shown and no other method will be

gtnhenbr [62]

x² - 4x = 12

x² - 4x - 12 = 0

x² + (2x - 6x) - 12 = 0

x² + 2x - 6x - 12 = 0

x (x + 2) - 6 (x + 2) = 0

(x - 6) (x + 2) = 0

Then the solutions are x = 6 or x = -2.

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2 years ago

A) b³(cm)³

Crazy boy [7]

Answer:

puedes decirme l indicación para poder resolverlo

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3 years ago

F(x)=15+x ; x=7 evaluating functions

Alinara [238K]

Answer:

Step-by-step explanation:

$f(x)15+x\\\\f(7)15+7\\\\\boxed{f(7)=22}$

Hope this helps.

3 0

3 years ago

Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

￼Can someone please give me the (Answers) to this? ... please ... I need help….

Can someone please give me the (Answers) to this? ... please ... I need help….