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2 years ago

Math need help on math

Mathematics

1 answer:

natulia [17]2 years ago

8 0

Answer:

The answer is 4

Step-by-step explanation:

As you can tell that GCF stands for Greatest Common Factor and the common factor of 36 and 68 is 4. Hope you get the answer you wanted!

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Cos^2x-sin^2x=sqrt 3/2

nalin [4]

$\cos^2x-\sin^2x=\cos2x=\dfrac{\sqrt3}2$

In the interval $[0,2\pi)$ , $\cos x$ takes on the value of $\dfrac{\sqrt3}2$ when $x=\pm\dfrac\pi3$ . In general, this happens for $x=\pm\dfrac\pi3+2n\pi$ where $n$ is any integer.

So, the solutions to this equation satisfy

$2x=\pm\dfrac\pi3+2n\pi$

or, dividing by 2,

$x=\pm\dfrac\pi6+n\pi$

for all integers $n$ .

7 0

3 years ago

NEED HELP ASAP PLEASE HELP

Daniel [21]

<AED = <BEC
2x+ 5 = 3x - 23
-x = - 28
x = 28

<AED = 2(28) + 5
<AED = 56 + 5
<AED = 61

answer
a. 61°

7 0

3 years ago

Sin pi/3 __ __ pi/6 = 1/2(sin pi/2 + sin pi/6)

Alinara [238K]

Notice that

• π/2 = π/3 + π/6

• π/6 = π/3 - π/6

Recall the angle sum identities for sine:

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

sin(x - y) = sin(x) cos(y) - cos(x) sin(y)

By adding these together, we get

sin(x + y) + sin(x - y) = 2 sin(x) cos(y)

==> sin(x) cos(y) = 1/2 (sin(x + y) + sin(x - y))

Now take x = π/3 and y = π/6 :

sin(π/3) cos(π/6) = 1/2 (sin(π/2) + sin(π/6))

So the blank should be filled with cos.

8 0

3 years ago

A small gym in Biloxi, Mississippi, averages about 50 customers on weekdays with a standard deviation of 10. It is safe to assum

andreyandreev [35.5K]

Answer:

It is very unusual as the probability to get a sample average of 75 or more customers if the manager had not offered the discount is 0.006

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 10

We are given that the distribution of number of customers is a bell shaped distribution that is a normal distribution.

In an attempt to increase the number of weekday customers, the manager offers a $10 membership discount on 5 consecutive weekdays and the sample mean of customers during this weekday period jumps to 75.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$