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Alik [6]
2 years ago
6

Math need help on math

Mathematics
1 answer:
natulia [17]2 years ago
8 0

Answer:

The answer is 4

Step-by-step explanation:

As you can tell that GCF stands for Greatest Common Factor and the common factor of 36 and 68 is 4. Hope you get the answer you wanted!

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Cos^2x-sin^2x=sqrt 3/2
nalin [4]
\cos^2x-\sin^2x=\cos2x=\dfrac{\sqrt3}2

In the interval [0,2\pi), \cos x takes on the value of \dfrac{\sqrt3}2 when x=\pm\dfrac\pi3. In general, this happens for x=\pm\dfrac\pi3+2n\pi where n is any integer.

So, the solutions to this equation satisfy

2x=\pm\dfrac\pi3+2n\pi

or, dividing by 2,

x=\pm\dfrac\pi6+n\pi

for all integers n.
7 0
3 years ago
NEED HELP ASAP PLEASE HELP
Daniel [21]
<AED = <BEC
2x+ 5 = 3x - 23
-x = - 28
x = 28

<AED = 2(28) + 5
<AED = 56 + 5
<AED = 61

answer
<span>a. 61°</span>
7 0
3 years ago
Sin pi/3 __ __ pi/6 = 1/2(sin pi/2 + sin pi/6)
Alinara [238K]

Notice that

• <em>π</em>/2 = <em>π</em>/3 + <em>π</em>/6

• <em>π</em>/6 = <em>π</em>/3 - <em>π</em>/6

Recall the angle sum identities for sine:

sin(<em>x</em> + <em>y</em>) = sin(<em>x</em>) cos(<em>y</em>) + cos(<em>x</em>) sin(<em>y</em>)

sin(<em>x</em> - <em>y</em>) = sin(<em>x</em>) cos(<em>y</em>) - cos(<em>x</em>) sin(<em>y</em>)

By adding these together, we get

sin(<em>x</em> + <em>y</em>) + sin(<em>x</em> - <em>y</em>) = 2 sin(<em>x</em>) cos(<em>y</em>)

==>   sin(<em>x</em>) cos(<em>y</em>) = 1/2 (sin(<em>x</em> + <em>y</em>) + sin(<em>x</em> - <em>y</em>))

Now take <em>x</em> = <em>π</em>/3 and <em>y</em> = <em>π</em>/6 :

sin(<em>π</em>/3) cos(<em>π</em>/6) = 1/2 (sin(<em>π</em>/2) + sin(<em>π</em>/6))

So the blank should be filled with cos.

8 0
3 years ago
A small gym in Biloxi, Mississippi, averages about 50 customers on weekdays with a standard deviation of 10. It is safe to assum
andreyandreev [35.5K]

Answer:

It is very unusual as the probability to get a sample average of 75 or more customers if the manager had not offered the discount is 0.006    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 10

We are given that the distribution of number of customers is a bell shaped distribution that is a normal distribution.

In an attempt to increase the number of weekday customers, the manager offers a $10 membership discount on 5 consecutive weekdays and  the sample mean of customers during this weekday period jumps to 75.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(sample average of 75 or more customers if the manager had not offered the discount)

P(x > 75)

P( x > 75) = P( z > \displaystyle\frac{75 - 50}{10}) = P(z > 2.5)

= 1 - P(z \leq 2.5)

Calculation the value from standard normal z table, we have,  

P(x > 610) = 1 - 0.994 = 0.006= 0.6\%

It is very unusual as the probability to get a sample average of 75 or more customers if the manager had not offered the discount is 0.006

b) Yes, the managers discount strategy worked as it increased the average number of customers from 50 customers to 75 customers.

3 0
3 years ago
the table the number of cakes an pies that gretchen sold at a bake sale last weekend she sold each cake for $8 an each pie for $
kaheart [24]

Answer:

48

Step-by-step explanation:

3 0
3 years ago
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