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Katen [24]
2 years ago
15

5. A sample of carbon dioxide (CO2) has a mass of 52.0 g. a. How many carbon atoms are present?

Chemistry
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

52.0 gof CO2 contains 7.1 *10^23 molecules

1 molecule of CO2 has a mass of 7.3*10^-23 grams

Explanation:

Step 1: Data given

Mass of CO2 = 52.0 grams

Molar mass of CO2 = 44.01 g/mol

Number of Avogadro = 6.022 * 10^23 / mol

Step 2: Calculate moles of CO2

Moles CO2 = Mass CO2 / molar mass CO2

Moles CO2 = 52.0 grams / 44.01 g/mol

Moles CO2 = 1.18 moles

Step 3: Calculate molecules in 1.18 moles CO2

Number of molecules = 1.18 moles * 6.022*10^23 = 7.1 *10^23 molecules

1 molecule of CO2

Number of moles = 1 / 6.022*10^23

Number of moles = 1.66 *10^-24

Mass CO2 = 1.66*10^-24 moles * 44.01 g/mol

Mass CO2 = 7.3*10^-23 grams

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Pachacha [2.7K]

i think the answer is c

5 0
4 years ago
A breathing mixture used by deep-sea divers contains helium, oxygen, and carbon dioxide. what is the partial pressure of oxygen
pentagon [3]
Pressure of the Mixture = 101.4 kpa  
Pressure of the helium phe = 82.5 kpa 
 Pressure of CO2 pco2 = 0.4 kpa.
 Partial pressure of oxygen = Pressure of the Mixutre - (Pressure of the
helium + Pressure of CO2)
 Partial pressure of oxygen = 101.4 - 82.5 - 0.4
 Partial pressure of oxygen = 18.5 kPa
7 0
3 years ago
Read 2 more answers
The peregrine falcon has been measured as Traveling up to 350 km/hr in a dive. if this falcon can fly to the moon at this speed,
soldi70 [24.7K]

Answer:

4 × 10⁶ sec

Explanation:

The distance between the earth and the moon = 384,400 km

The speed of the peregrine falcon = 350 km/hr

Considering,

Distance = Speed × Time

So,

Time = Distance / Speed = 384,400 km / 350 km/hr = 1098.28571 hrs

Also,

1 hr = 3600 sec

So,

1098.28571 hrs = 3600 × 1098.28571 s ≅ 4 × 10⁶ sec

<u>Thus time taken by peregrine falcon if falcon fly to the moon = 4 × 10⁶ sec </u>

3 0
3 years ago
Calculate either [H3O+] or [OH−] for each of the solutions at 25 °C. Solution A: [OH−]=1.55×10−7 M Solution A: [H3O+]= M Solutio
Ahat [919]

Answer: A. [H_3O^+]=0.64\times 10^{-7}M

B. [OH^-]=0.11\times 10^{-5}M

C. [OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

Thus solution B is basic in nature.

Explanation:

pH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH for acidic solutions is less than 7, for basic solutions it is more than 7 and for neutral solutions it is equal to 7.

pH=-\log [H^+]

pOH=-log[OH^-]

pH+pOH=14

or [H^+][OH^-]=10^{-14}

A. [OH^-]=1.55\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{1.55\times 10^{-7}}=0.64\times 10^{-7}M

pH=-log[H_3O^+]=-log[0.64\times 10^{-7}]=7

B. [H_3O^+]=9.43\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.43\times 10^{-9}}=0.11\times 10^{-5}M

pH=-log[H_3O^+]=-log[9.43\times 10^{-9}]=8

C. [H_3O^+]=0.000775M

[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

pH=-log[H_3O^+]=-log[0.000775]=3

Thus solution B is basic.

4 0
3 years ago
What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?
Eddi Din [679]

Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

6 0
3 years ago
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