How would you find how many unpaired electrons are in a compound? Ex. unpaired electrons in aluminum in aluminum II oxide.
1 answer:
You would have to multiply or either divide
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<span>6. Because the general formula for alkenes is CnH2n</span>
Answer:
Nitrogen non metal
Gain 3 electrons
Negative ion N3-
Barium metal
Lose electrons
Positive charge
Selinium non metal
Gain electron
Negative charge
Cesium metal
Lose electrons
Positive charge
Explanation:
O.N. of Na = +1
O.N. of O = -2
Let, O.N. of Tin = x
1*2 + x + -2*2 = 0
2+x-4 = 0
x-2 = 0
x = 2
SO OPTION C IS YOUR ANSWER......
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