Answer:
The concentration of the dilute sample will be 0.361 g/ml
Explanation:
If a solution is diluted into 1:10 ratio then the amount of solute of that solution will be decreased by 10 times.
The initial concentration of the stock solution was 3.61g/ml but when the solution is diluted in 1:10 ratio the solute concentration is also decreased by 10 times.SO at present the solute concentration becomes 3.61/10=0.361 g/ml.
Answer:
Explanation:
The modern model recognizes particles in the atom, whereas Dalton's model does not.
The molar mass of the hydrate is 278.06
The molar mass of the anhydrous salt is 151.92
The molar mass of water in the hydrate is 126.14
Answer:
<em>Butane has only two isomers and pentane has just three, but some hydrocarbons have many more isomers than these. As you increase the number of carbon atoms in a hydrocarbon, the number of isomers quickly increases.</em>
<em />
The equilibrium reaction is
2 NOBr ⇄ 2 NO + Br₂
The initial molarity of NOBr is 0.174 mol/1 L = 0.174 M. Let's apply the ICE approach which stands for Initial-Change-Equilibrium.
2 NOBr ⇄ 2 NO + Br₂
I 0.174 0 0
C -2x +2x +x
----------------------------------------------------
E 0.174-2x 2x x
Since E for Br₂ is 1.79*10⁻² M, then that means x = 1.79*10⁻² M. We can compute E for the other compounds.
E for NOBr = 0.174 - 2(1.79*10⁻²) = 0.1382 M
E for NO = 2(1.79*10⁻²) = 0.0358 M
The expression for Kc according to the reaction is:
Kc = [NO]²[Br₂]/[NOBr]²
Kc = [0.0358]²[1.79*10⁻²]/[0.1382]²
<em>Kc = 1.2×10⁻³</em>
