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4 years ago

Define and explain auto-ionization of water??? Explain please??

Chemistry

2 answers:

Oduvanchick [21]4 years ago

6 0

Answer:

in pure water, H2O molecules undergo a reaction in which two molecules react in such a way that one molecule give its H+ ion to other molecule and become a hydroxyl ion(OH-) and molecule which gain H+ ion become H3O+ ion.

Explanation:

H2O + H2O ⇄ ( H3O+) +( OH-)

icang [17]4 years ago

5 0

Answer:

Hey there!

Auto-ionization of water is an ionization reaction in pure water or in another aqueous solution, in which a water molecule, H2O, loses the nucleus of one of its hydrogen atoms to become a hydroxide ion, OH−.

Let me know if this helps :)

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7 points

Free_Kalibri [48]

Answer: 12 ( answer not among the option)

Explanation:

From the equation of reaction; P4O10+ H2O -----> H3PO4, it is unbalanced.

One can only get the exact number of ''Hydrogen atom'' if it is well balanced.

Adding '4' to H3PO4 on the RHS and '6' to H2O on LHS of the equation would give a balanced equation such as;

P4O10 + 6H2O -----> 4 H3PO4

Therefore the number of hydrogen atoms found on the reactant is 12.

6 0

3 years ago

Which option below describes a chemical property of a substance?

boyakko [2]

Answer:

Explanation:

Rust is a chemical change (reaction) all of the other options only change the state meaning that it is a physical reaction.

4 0

3 years ago

Read 2 more answers

What is the smallest component or the most basic building block of any element ? A. An Atom, B.a compound C.gas D.element

poizon [28]

The answer to the question is A) an atom.

4 0

3 years ago

Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .