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ohaa [14]
4 years ago
10

Define and explain auto-ionization of water??? Explain please??

Chemistry
2 answers:
Oduvanchick [21]4 years ago
6 0

Answer:

in pure water, H2O molecules undergo a reaction in which two molecules react in such a way that one molecule give its H+ ion to other molecule and become a hydroxyl ion(OH-) and molecule which gain H+ ion become H3O+ ion.

Explanation:

H2O + H2O ⇄ ( H3O+) +( OH-)

icang [17]4 years ago
5 0

Answer:

Hey there!

Auto-ionization of water is an ionization reaction in pure water or in another aqueous solution, in which a water molecule, H2O, loses the nucleus of one of its hydrogen atoms to become a hydroxide ion, OH−.

Let me know if this helps :)

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makvit [3.9K]

the awnser is exothermic (combustion)


4 0
4 years ago
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What kind of non-flowering plant produces seeds instead of spores?
Pie

Answer:

The answer to your question is Ferns

Explanation:

Ferns are called nonflowering plants and produce spores instead of seeds.

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3 years ago
Chemical bonding for <br><br> Rb &amp; nitrogen,<br><br> Need help!!!
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Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the r
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Answer:

∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

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1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

8 0
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In the metric system kilo is an abbreviation for 10,000
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10 kilo

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