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andrew11 [14]
2 years ago
9

For each of the bonds listed, tell which atom is more negatively charged a. C--H b. C--N c. C--S d. C--O

Chemistry
1 answer:
blondinia [14]2 years ago
5 0

Explanation:

The atom is considered to be more electronegative , when it has the tendency to get a slight negative i.e. , delta negative charge on it , and the other atom gets a delta positive charge .

In the periodic table ,

As we go left to right in the periodic table , the electronegativity increases ,

and

As we go top to bottom , the electronegativity decreases .

Hence , from the option given in the question ,

a. C--H , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , Carbon is more electronegative than hydrogen .

b. C--N ,  the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , nitrogen is more electronegative than Carbon .

c. C--S , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , sulfur is more electronegative than Carbon .

d. C--O , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , oxygen is more electronegative than Carbon .

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Carly lives in an area with temperatures that are always very warm. Carly also lives in an area that is close to the equator. Wh
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When 5ml of HCl was added
777dan777 [17]

Answer:

A. There was still 140 ml of volume available for the reaction

Explanation:

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Where;

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2 years ago
Ben has a snack with a combination of raisins, chocolate pieces, and nuts. As he eats the snack, Ben picks out all of the raisin
erastova [34]

Answer:

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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
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Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

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k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

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k=\frac{0.693}{t_{1/2}}

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t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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3 years ago
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