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3 years ago

Construct an accurate copy of triangle DEF. Check that EF = 4.6 cm.

Mathematics

1 answer:

garri49 [273]3 years ago

7 0

Answer:

Angles on a straight line add up to 180°

Therefore, the interior angle D of the triangle = 180 - 150 = 30°

Draw a horizontal line of 8 cm - label DE.

Measure an angle of 30° from point D and draw a line.

Measure an angle of 90° from point E and draw a line.

These 2 lines will intersect at point F.

Erase the part of the lines that extend past the point of intersection.

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An elephant can run of a mile in 36 seconds. At this rate, which expression can be used to determine how fast an elephant runs i

Mice21 [21]

Answer:

The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

Solution:

Given that,

Distance covered by an elephant in 36 seconds is equal to 1 mile

Therefore, distance covered by the elephant in 1 second is $\frac{1}{36}$ mile

Therefore, distance covered by the elephant in 60 seconds (60 seconds = 1 minute) is

$\frac{1}{36} \times 60=\frac{5}{3} \text { miles }$

Therefore, distance covered by the elephant in 60 minute (60 minute = 1 hour) is

$\frac{5}{3} \times 60=100 \text { miles per hour }$

Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

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3 years ago

In ΔTUV, v = 990 inches, t = 840 inches and ∠U=148°. Find the length of u, to the nearest inch.

Scilla [17]

Answer:

the answer is 1760

Step-by-step explanation:

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3 years ago

From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

8 0

3 years ago

Read 2 more answers

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Liono4ka [1.6K]

Answer:

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3 years ago

Read 2 more answers

-2(x + 2) = -2x ++ 5x -1

earnstyle [38]

Answer:

-⅗ = x

Step-by-step explanation:

Here is what you get when you distribute the -2 on the left side of the equivalence symbol and combine like-terms on the right side of the equivalence symbol:

-2x - 4 = 3x - 1

Here is the solution:

-2x - 4 = 3x - 1

-3x -3x

----------------

-5x - 4 = -1

4 +4

----------------

-5x = 3

----- -----

-5 -5

x = -⅗

I am joyous to assist you anytime.

8 0

3 years ago

Construct an accurate copy of triangle DEF. Check that EF = 4.6 cm. ​

Construct an accurate copy of triangle DEF. Check that EF = 4.6 cm.