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2 years ago

Answer the questions below. Be sure to mark all answers that apply.

Mathematics

1 answer:

BabaBlast [244]2 years ago

3 0

Answer:

Part A: Only 460 is divisible by 2

Part B: 385, and 460 are divisible by 5

Part C: Only 460 works for this one

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Create an expression equivalent to 2 (3x =1) 3x+4 using the least number of terms

Mariana [72]

Answer:

$18x^2 + 18x -8$

Step-by-step explanation:

To use the least number of terms, simplify the expression. To simplify, distribute into the parenthesis and combine like terms.

$2(3x-1)(3x+4) = 2(9x^2-3x+12x-4) = 2(9x^2+9x-4) = 18x^2 + 18x -8$

6 0

3 years ago

What is the length of side AB of parallelogram ABCD? units 4g - 8 B q+4

Andrews [41]

Answer:

8 units

Step-by-step explanation:

» Concepts

Parallelogram Side Theorem states that the opposite sides of a parallelogram are congruent, meaning they have the same length.

» Application

In this case, we're asked to apply the theorem to find the value of q and then find the length of AB. Thus, we have to set up the equation 4q - 8 = q + 4.

» Solving

Step 1: Subtract q from both sides.

$4q-8-q=q+4-q$
$3q-8=4$

Step 2: Add 8 to both sides.

$3q-8+8=4+8$
$3q=12$

Step 3: Divide both sides by 3.

$3q/3 = 12/3$
$q=4$

Step 4: Plug in the value of q for side AB.

$4(4)-8$
$16-8$
$8$

Therefore, the answer is 8 units.

6 0

2 years ago

What's the equation of the graph shown above?

nadezda [96]

Answer:

dfdff3ffdcdcdcd

Step-by-step explanation:

ccdcdcc

4 0

3 years ago

PLS HELP! WILL GIVE POINTS NO WRONG ANSWERS.

lubasha [3.4K]

Answer:

-98/-7+13= 27!

Step-by-step explanation:

Sarahs number is 27!

5 0

3 years ago

Read 2 more answers

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma

bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a) $=\frac{v-u}{t}$

$a=\frac{60\times 60\times 60}{4}$

$a=54\times 10^3 mi/h^2$

To reach a speed of 183.58mi/h with an acceleration of $54\times 10^3 mi/h^2$

Using equation of motion

v=u+at

$183.58=0+(54\times 10^3)t$

$t=\frac{183.58}{54\times 10^3}$

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

$s=ut+\frac{1}{2}at^2$

$5=0+\frac{1}{2}\times 54\times 10^3 \times t^2$

t=0.01360 hour

or $t=48.98\approx 49 s$

7 0

3 years ago