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Oxana [17]
3 years ago
11

The greater a habitat's biodiversity, the greater will be the habitat's, sustainability over time with varying conditions sustai

nability over time with varying conditions consumption of energy in the form of sunlight consumption of energy in the form of sunlight temperature ranges across the seasons temperature ranges across the seasons distance to the nearest water source distance to the nearest water source
Chemistry
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

<u><em>The correct answer is:</em></u><u><em> </em></u>  sustainability over time with varying conditions.

Explanation:

A habitat can be defined as the physical and geographical conditions that will positively influence the development of life, in any form.

Therefore, it is correct to say that sustainability over time with favorable conditions will favor the greatness of the habitat.

Sustainability is the ability to preserve a system for the maintenance of future life, so it is ideal for there to be sustainable development across society, so that natural resources are preserved so that biodiversity continues to exist.

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What is the formula of water and what are the two ions that it is made of?
ahrayia [7]
H20. 2 of hydrogen and oxygen
6 0
3 years ago
What mass of potassium iodide is needed to prepare 5.60 L of a 1.13 M solution
MrMuchimi
Given that the question gives us concentration (M) and volume, we can use these so get moles. remember that Molarity (M)= mol/ Liters, so if we want the moles, then

moles= M x L

moles= 1.13 x 5.60= 6.33 moles KI

now to get the mass in grams, we need the molar mass of potassium iodide (KI) which can be determined using the periodic table and add the masses of each atom.

molar mass KI= 39.1 + 127= 166.1 g/mol

6.33 mol (166 g/ 1 mol)= 1050 grams KI


8 0
3 years ago
Attempt 1 of 1
Fittoniya [83]
I’m not 100% positive but quartz would make sense
5 0
3 years ago
Read 2 more answers
What is always true of a strong acid?
sveta [45]

Strong acids provide more H+ in the aqueous solution than the weak acids. This excess amount of H+ conducts more electricity in the solution.

Explanation:

The strong acid provides more H+ ion whereas the weak acids produce less H+ in the aqueous solution resulting in less amount of electricity conduction in the solution.

Weak acid- lesser amount of H+ produced

Strong acid- greater amount of H+ ( proton) produced.

4 0
3 years ago
Read 2 more answers
How many moles, kmols in: 100 g of CO2, 1 litre of ethyl alcohol of density 0.789 g/cm3 and a) 1.5m3 of O2 at 25°C and 1 atm. b)
Nutka1998 [239]

Explanation:

1) Mass of carbon dioxide = 100 g

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide =\frac{100 g}{44 g/mol}=2.273 moles

1 mol = 0.001 kmol

2.273 moles= 2.273 × 0.001 kmol = 2.273\times 10^{-3} kmol

2) 1 liter of ethyl alcohol of density 0.789 g/cm^3

Volume of ethyl alcohol ,V= 1 L = 1000 mL

Density of ethyl alcohol =d = 0.789 g/cm^3

1 cm^3=1 mL

Mass of ethyl alcohol = m

m=d\times V=0.789 g/cm^3\times 1000 mL=789 g

Molar mass of  ethyl alcohol = 46 g/mol

Moles of ethyl alcohol = \frac{789 g}{46 g/mol}=17.152 mol

17.152 mol=17.152\times 0.001 kmol=1.7152\times 10^{-4} kmol

3) Volume of oxygen gas,V =1.5 m^3=1500 L

1 m^3= 1000 L

Temperature of the gas = T= 25°C = 298.15 K

Pressure of the gas ,P= 1 atm

Moles of oxygen gas = n

PV=nRT

n=\frac{RT}{PV}=\frac{0.0821 atm L/mol K\times 298.15 K}{1 atm\times 1500 L}=0.01632 mol

0.01632 mol = 0.01632 × 0.001 kmol=1.632\times 10^{-5} kmol

4) Volume water in mixture = 1 L

Density of water =  1000 kg/m^3=\frac{1,000,000 g}{1000 L}=1000 g/L

Mass of water = 1000 g/L\times 1 L = 1000 g

Volume of alcohol = 2.5 L

Density of alcohol =  789 kg/m^3=\frac{789000 g}{1000 L}=789 g/L

Mass of alcohol = 789 g/L\times 2.5 L = 1972.5 g

Mass of mixture = 1000 g + 1972.5 g = 2972.5 g

Mass percentage of water :

\frac{1000 g}{2972.5 g}\times 100=33.64\%

Mass percentage of alcohol :

\frac{1972.5 g}{2972.5 g}\times 100=66.36\%

Moles of water :

n_1=\frac{1000 g}{18 g/mol}=55.55 mol

Moles of alcohol =

n_2=\frac{1972.5 g}{46 g/mol}=42.88 mol

Mole fraction of water :

\chi_1=\frac{n_1}{n_1+n_2}=\frac{55.55 mol}{55.55 mol+42.88 mol}=0.5644

Mole fraction of alcohol :

\chi_2=\frac{n_2}{n_1+n_2}=\frac{42.88 mol}{55.55 mol+42.88 mol}=0.4356

3 0
3 years ago
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