Since none answered from Indian NCERT yet, let me give a simple definition from ICSE..
Latent Heat of vapourisation is the heat energy required to convert unit mass of a substance from liquid to vapour state WITHOUT ANY CHANGE IN ITS TEMPERATURE....
hope this helps!
Answer:
D-the measure of temperature in a system
Answer:
Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.
Explanation:
i just took the test , i hope this helps:)
Answer: 5.747 * 10^14 Hz
Explanation:
Convert 522nm to m = 522 * 10^-9 m (since 1nm=10^-9m)
If c = wavelength * frequency, where c is the speed of light (3.0 * 10^8 m/s), then you can manipulate the equation to solve for frequency (f).
f = c / wavelength
Plug in the given numbers:
f = (3.0 * 10^8) / (10^-9)
f = 5.747 * 10^14 Hz
Answer:
0.9715 Fraction of Pu-239 will be remain after 1000 years.
Explanation:
Where:
= decay constant
=concentration left after time t
= Half life of the sample
Half life of Pu-239 = 
[
![\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B0.693%7D%7B24%2C000%20y%7D%3D2.8875%5Ctimes%2010%5E%7B-5%7D%20y%5E%7B-1%5D)
Let us say amount present of Pu-239 today = 
A = ?
![A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}](https://tex.z-dn.net/?f=A%3Dx%5Ctimes%20e%5E%7B-2.8875%5Ctimes%2010%5E%7B-5%7D%20y%5E%7B-1%5D%5Ctimes%201000%20y%7D)
0.9715 Fraction of Pu-239 will be remain after 1000 years.
