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iVinArrow [24]
4 years ago
13

Do gold and silver have the same extensive properties​

Chemistry
2 answers:
Pepsi [2]4 years ago
8 0

Answer:

They do not

Explanation:

Gold is more advanced

harkovskaia [24]4 years ago
3 0
No they do not share the same extensive properties
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Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +
Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0
3 years ago
Read 2 more answers
Hazardous materials are grouped into classes identifying their.
saveliy_v [14]

Hazardous materials are grouped into classes identifying their similarities in composition and structure.

<h3>Why hazardous materials are grouped into classes?</h3>

The hazardous materials are grouped into classes in order to tell us about the severity of hazard and it is done on the basis of similarity in composition.

So we can conclude that hazardous materials are grouped into classes identifying their similarities in composition and structure.

Learn more about hazardous here: brainly.com/question/7310653

8 0
2 years ago
Can someone help with this???
e-lub [12.9K]

Answer:

2Mg(s) +O₂(g) → 2MgO(s)

Explanation:

Mg(s) +O₂(g) → MgO(s)

When a chemical equation is balanced, the number of atoms of each element is equal on both sides of the arrow. We usually balance O and H last.

In this case, the number of Mg atoms is equal on both sides. Thus, let's move on to balance the O atoms. On the left side, there are 2 O atoms, while there is only 1 O atom on the left side. Thus, write a '2' in front of MgO.

Mg(s) +O₂(g) → 2MgO(s)

Now, the number of Mg atoms is not equal. Write a '2' in front of Mg to balance it.

2Mg(s) +O₂(g) → 2MgO(s)

The equation is now balanced with 2 Mg atoms and 2 O atoms on each side.

6 0
3 years ago
The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. half dollars would be in a stack of the same heigh
zhannawk [14.2K]

Answer:

To equal the height of the Gateway Arch in St. Louis, it would take <u>76810 half dollars. </u>

Explanation:

If the Gateway Arch in St. Louis is 630 feet high, how many half dollars will it take to equal the height if each half dollar is 2.15mm thick?

First, we convert the ft to cm and the cm to mm.

- 1 ft = 30.48 cm

630 ft = 19202.4 cm

- 19202.4 cm = 192024 mm

Now, if a half dollar is 2.15 mm thick, how many half dollars would it take to equal the height of 192024 mm?

1 half dollar = 2.15 mm

X                 = 192024 mm

X = 192024 mm / 2.15 mm

X = 76810 half dollars.

5 0
3 years ago
Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)
vampirchik [111]

Answer: Oxygen is the limiting reagent.

Explanation: CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)

As can be seen from the given balanced equation:

3 moles of O_2 reacts with 1 mole of CS_2

1.52 moles of O_2 reacts with=\frac{1}{3}\times 1.52=0.51moles of CS_2

Thus O_2 is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of CS_2 will remain as such and thus  CS_2 is an excess reagent.

6 0
3 years ago
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