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seropon [69]
4 years ago
15

What is the hardest mineral listed here? A. quartz B. calcite C. gypsum D. corundum

Chemistry
2 answers:
krok68 [10]4 years ago
4 0

Answer:D. corundum

Explanation:

Corundum is a hard mineral. It is tough and stable in nature. It is the hardest mineral after diamond. It remains unaffected by the treatment of acids and environmental agents. Translucent brown color corundum is commonly found in nature.

a_sh-v [17]4 years ago
3 0
The answer would be D. The only minerals harder than corundum is diamond.
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Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.6
yulyashka [42]

Answer:

1.8 g

Explanation:

Step 1: Write the balanced equation

CH₃CH₃(g) + 3.5 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)

Step 2: Determine the limiting reactant

The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:112.0 = 0.2684:1.

The experimental mass ratio of CH₃CH₃ to O₂ is 0.60:3.52 = 0.17:1.

Thus, the limiting reactant is CH₃CH₃

Step 3: Calculate the mass of CO₂ produced

The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:88.02.

0.60 g CH₃CH₃ × 88.02 g CO₂/30.06 g CH₃CH₃ = 1.8 g

4 0
3 years ago
commercial cold packs consist of solid NH4NO3 and water. In a coffee-cup calorimeter, 5.60g NH4NO3 is dissolved in 100g of water
fgiga [73]

Answer:

-1.37 kJ/mol

Explanation:

The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 5.60 g

Specific heat = 4.18 J/g°C

\Delta T=17.9-22.0\ ^0C=-4.1\ ^0C

So,  

\Delta H=-1.25\times 4.18\times 3.9\ J=-95.9728\ J

Negative sign signifies loss of heat.  

Also, 1 J = 0.001 kJ

So,  

\Delta H=-0.096\ kJ

Also,

Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{5.60\ g}{80.043 \ g/mol}

Moles= 0.06996\ mol

Thus, \Delta H=-\frac{0.096}{0.06996}\ kJ/mol=-1.37\ kJ/mol

6 0
3 years ago
an unknown volume of gas has a pressure of 0.50 atm and temperature of 325k. if the pressure is raised to 1.2atm and the tempera
postnew [5]
117 L. You can start by making a table to organize the information you are given. Then, you can use the formula PV/T=PV/T and plug in the numbers you have. You then solve for the missing volume. Remember that the initial pressure, temperature, and volume should be on one side of the equal sign, and the final pressure, volume, and temperature should be on the other side.

6 0
3 years ago
The following equations are half reactions and reduction potentials. Ag+ (aq) + e– Ag(s) has a reduction potential of +0.80 V. C
Lady bird [3.3K]

Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.

Explanation :

The given half reaction are :

1st half reaction : Ag^+(aq)+e^-\rightarrow Ag(s)

The reduction potential of this reaction = +0.80 V

2nd half reaction : Cr^{3}+(aq)+3e^-\rightarrow Cr(s)

The reduction potential of this reaction = -0.74 V

From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.

Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.

The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.

Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.


5 0
4 years ago
Read 2 more answers
Kahdbiaddsk;wvfodas vs;oi vsd;iv sdv;sidv s;vowdbvw;dichvbwdv;iwebfwd;iwdbcv;wkfbsdliasbv;soqivbasd
storchak [24]

Answer:

I am not positive sorry

6 0
3 years ago
Read 2 more answers
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