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algol [13]
2 years ago
7

8) How many solutions does the following equation have? 0 = 9x2 - 6x + 1

Mathematics
1 answer:
sweet [91]2 years ago
4 0
I’m guessing it’s 9x^2 -6x + 1 but this is basically just one. (1/3,0) use desmos if you’re curious
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L want to know the sum result.10+67×2=?<br>​
Volgvan

Answer:

144

Step-by-step explanation:

<u>Step 1:  Multiply </u>

10 + (67 * 2)

10 + 134

<u>Step 2:  Combine </u>

10 + 134

144

Answer: 144

3 0
3 years ago
Read 2 more answers
Can someone help me solve this.​
Amanda [17]

Answer:

equilateral:  E

scalene:  F

isosceles:  G

Step-by-step explanation:

equilateral = all sides are equal

scalene = no sides are equal

isosceles = two sides are equal

4 0
3 years ago
How would I get 517527*6617 by dividing 57765566 and 62762526272​la la la la la la la
ankoles [38]

Answer:

I'm not able to answer your question

Step-by-step explanation:

due to the fact that you can't divide with multiplication I'm unsure on how to help you

4 0
3 years ago
Laura sees a horse pulling a buggy. She wonders how it can accelerate if the action of the horse pulling the cart would causes a
KatRina [158]

Answer:

The net forces exerted on the horse and cart are not the same, so they are not balanced forces.

Step-by-step explanation:

Please see the Newton's 2nd Law which states  that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.

As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.

If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.

If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.

7 0
3 years ago
Read 2 more answers
(2/3) / (-1/2)<br> How do I divide these 2 fractions?
dsp73

Answer:

Step-by-step explanation:

2/3*(-2/1)

-\frac{4}3}

Hope it helps! Please mark Brainliest if it does!

4 0
3 years ago
Read 2 more answers
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