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ivolga24 [154]
4 years ago
7

In Part 5 of Form 940, Peterson Company reported FUTA tax liabilities as follows:

Business
1 answer:
kari74 [83]4 years ago
6 0

Answer:

First quarter: <em>amount </em>$0 <em>date: </em>-

Second quarter: <em>amount </em>$606.60 <em>date:</em> July 31

Third quarter: <em>amount </em>$0 <em>date: </em>-

Fourth quarter: <em>amount </em>$537 <em>date:</em> January 31

Explanation:

As per IRS, in part 5 of Form 940, Peterson Company will report FUTA tax liability by Quarter only if Total FUTA Tax after Adjustments is more than $500. So, Peterson Company is not required to pay FUTA tax until FUTA tax liability is more than $500 and if in any particular quarter the FUTA tax liability is less than $500 then the cumulative amount will be taken with the next quarter until the FUTA tax liability reaches more than $500. So first quarter will add up with quarter 2 and the FUTA tax liability will be $606.60 & third quarter will add up with fourth quarter and the FUTA tax liability will be $537.  

As far as due dates are concerned, the due date of the first quarter is the month after the end of first quarter. So, for the quarter from January to March the Due Date will be April 30, from April to June the Due Date will be July 31, from July to September the Due Date will be October 31, from October to December the Due Date will be January 31.

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1 year ago
A fast-food restaurant has determined that the chance a customer will order a soft drink is 0.90. The proba- bility that a custo
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Answer:

(a) The probability that the order will include a soft drink and no fries is 0.45.

(b) The probability that the order will include a hamburger and fries is 0.48.

Explanation:

Let the events be denoted as follows:

S = an order of soft drink

H = an order of hamburger

F = an order of french fries.

Given:

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P (H) = 0.60

P (F) = 0.50

(a)

It is provided that the event of ordering a soft drink and fries are independent.

If events A and B are independent then the probability of event (A ∩ B) is:

P(A\cap B)=P(A)\times P(B)

Compute the probability that the order will include a soft drink and no fries as follows:

P(S\cap \bar F)=P(S)\times P(\bar F)\\=P(S)\times[1-P(F)]\\=0.90\times (1-0.50)\\=0.45

Thus, the probability that the order will include a soft drink and no fries is 0.45.

(b)

It is provided that the conditional probability that a customer will order fries given that he/she has already ordered a hamburger as, P (F|H) = 0.80.

The conditional probability of an event B given another event A has already occurred is:

P(B|A)=\frac{P(A\cap B}{P(A)}

Compute the probability that the order will include a hamburger and fries as follows:

P(F|H)=\frac{P(H\cap F)}{P(H)}\\P(H\cap F)=P(F|H)\times P(H)\\=0.80\times 0.60\\=0.48

Thus, the probability that the order will include a hamburger and fries is 0.48.

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