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aleksklad [387]
2 years ago
9

Find the perimeter and total area of the compositor shape shown below. All measurements are given in inches.

Mathematics
1 answer:
Assoli18 [71]2 years ago
4 0

\bold{\huge{\pink{\underline{ Solution }}}}

<h3><u>Given</u><u> </u><u>:</u><u>-</u></h3>

  • The radius of the hemisphere is 3 units
  • The height of the hemisphere is 3 units
  • The height of the triangle is 4 units
  • The other two sides of triangle is 5 units each

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We have to find the area and perimeter of the composite solid ?</u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

We have given one composite which is composed of hemisphere and triangle

<u>We </u><u>know </u><u>that</u><u>, </u>

<u>Perimeter </u><u>of </u><u>hemisphere </u>

\bold{\red{ = }}{\bold{\red{\pi{r}}}}

Perimeter of the triangle

\bold{\pink{ = S + S + S }}

[ Both the figures have common base area ]

<h3><u>Therefore</u><u>, </u></h3>

Total perimeter of the composite solid

\sf{ = 5 + 5 + }{\sf{\dfrac{22}{7}}}{\sf{\times{r}}}

\sf{ = 10 + }{\sf{\dfrac{22}{7}}}{\sf{\times{3}}}

\sf{ = 10  + }{\sf{\dfrac{66}{7}}}

\sf{ = }{\sf{\dfrac{70 + 66}{7}}}

\sf{ = }{\sf{\dfrac{136}{7}}}

\bold{ = 19.42\: inches }

Thus, The perimeter of the composite solid is 19.42 inches

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>composite </u><u>solid </u>

We know that,

Area of hemisphere

\bold{\blue{ = }}{\bold{\blue{\dfrac{1}{2}}}}{\bold{\blue{\pi{r²}}}}

\sf{ = 0.5}{\sf{\times{\dfrac{22}{7}}}}{\sf{\times{ 3 }}}{\sf{\times{ 3 }}}

\sf{ = 0.5}{\sf{\times}}{\sf{\dfrac{22}{7}}}{\sf{\times{ 9 }}}

\sf{ = 0.5}{\sf{\times{\dfrac{198}{7}}}}

\sf{ = }{\sf{\dfrac{99}{7}}}

\bold{ = 14.14\: inches }

<u>We </u><u>also </u><u>know </u><u>that</u><u>, </u>

Area of triangle

\bold{\purple{ = }}{\bold{\purple{\dfrac{1}{2}}}}{\bold{\purple{\times{ Base}}}}{\bold{\purple{\times{height }}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ = }{\sf{\dfrac{1}{2}}}{\sf{\times{ 4 }}}{\sf{\times{3}}}

\sf{ = 2 }{\sf{\times{ 3 }}}

\bold{ = 6\: inches }

  • [Note :- Both the figures have common base area. So for triangle base area will be 6/2 = 3 in.]

<h3><u>Therefore</u><u>,</u><u> </u></h3>

Total Area of the composite solid

\sf{ = 14.14 + 6}

\bold{\red{ = 20.14\: inches }}

Hence, The perimeter and area of composite solid is 19.42 inches and 20.14 inches .

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