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azamat
2 years ago
15

What is the diameter of the earth? Explain how long it will take to measure the entire sun.

Physics
2 answers:
andreev551 [17]2 years ago
5 0

Answer:

Distance between earth and sun, around 150 million km, is defined as one Astronomical Unit (AU). The radius of the Sun, Run is around 700,000 km. The orbital speed of Earth is around 30 km/s.

Explanation:

jok3333 [9.3K]2 years ago
5 0
You know that the Earth goes around the Sun, once per year. Let's suppose that the path the Earth takes, its "orbit", is a circle. If the Earth's orbit is perfectly circular, then that means the Earth is always the same distance from the Sun. And if it's always the same distance away, this means that the Sun would always appear to have the same size in the sky. Another way to say this is that the Sun's angular diameter would appear to be constant.
Investigation:

How can we test this hypothesis? Start by grabbing four pictures of the Sun, taken a few months apart. (Ask yourself: Why four? Why not just any two, six months apart?) Load the four pictures into your browser, or your image processor (NIH Image, ImagePC, etc.), and LOOK. Is the Sun the same size in all four images?
There are a couple of ways to compare the relative sizes. Most straightforward is to make a ruler out of a piece of paper and hold it up to the computer screen; use the same ruler to measure all four images. If you have an image processor like NIH Image or ImagePC, another way is to put the cursor on the left- and then right-hand edges of the Sun, and then use the printout of the cursor position to count how many pixels across is the Sun.

More Technical: Also in an image processor like NIH Image or ImagePC, you can use the "Image Math" selection under the "Process" menu. Choose one image (say, January) as the 'standard' and then take turns subtracting the other images away from the 'standard.' What do you see?

Discussion:

If the Sun is the same diameter in every image, then the comparison of the four images should reveal only where sunspots have appeared/disappeared, but nothing significant about the Sun's edge. But if the solar diameter has changed in the months between when the images were taken, you should be able to detect this with your paper ruler. If you try the More Technical exercise, subtracting one image from another, then the result of the subtraction should show a ring, an annulus, that corresponds to the change in angular diameter. An example of this subtraction is provided at URL:
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The answer is <span>B. by increasing its mass. Hope it help!</span>
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3 years ago
At what point is the velocity vector changing most rapidly?
agasfer [191]

Answer:

It is changing at the same rate at all  points.

A velocity vector represents the rate of change of the position of an object. The magnitude of a velocity vector gives the speed of an object while the vector direction gives its direction. Velocity vectors can be added or subtracted according to the principles of vector addition.

Explanation:

Velocity as a Vector Quantity

Velocity is a vector quantity that refers to "the rate at which an object changes its position." Imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. While this might result in a frenzy of activity, it would result in a zero velocity. Because the person always returns to the original position, the motion would never result in a change in position. Since velocity is defined as the rate at which the position changes, this motion results in zero velocity. If a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. Every step must go into moving that person further from where he or she started. For certain, the person should never change directions and begin to return to the starting position.

Velocity is a vector quantity. As such, velocity is direction aware. When evaluating the velocity of an object, one must keep track of direction. It would not be enough to say that an object has a velocity of 55 mi/hr. One must include direction information in order to fully describe the velocity of the object. For instance, you must describe an object's velocity as being 55 mi/hr, east. This is one of the essential differences between speed and velocity. Speed is a scalar quantity and does not keep track of direction; velocity is a vector quantity and is direction aware.

4 0
3 years ago
9.1 x 105 – 7.2 x 105<br> =
Maslowich

Answer:

1.9 x 10⁵

Explanation:

I <em>ASSUME </em>your question is supposed to read

9.1 x 10⁵ – 7.2 x 10⁵ =

9.1 - 7.2 = 1.9 and the powers are the same so just tag them along

its the same as

910000 - 720000 = 190000

1.9 x 105 could be another possibility if the question is actually posed correctly.

6 0
3 years ago
An important diagnostic tool for heart disease is the pressure difference between blood pressure in the heart and in the aorta l
butalik [34]

Answer:

a)   f ’’ = f₀ \frac{1 + \frac{v}{c} }{1- \frac{v}{c} } , b)   Δf = 2 f₀ \frac{v}{c}

Explanation:

a) This is a Doppler effect exercise, which we must solve in two parts in the first the emitter is fixed and in the second when the sound is reflected the emitter is mobile.

Let's look for the frequency (f ’) that the mobile aorta receives, the blood is leaving the aorta or is moving towards the source

                    f ’= fo\frac{c+v}{c}

This sound wave is reflected by the blood that becomes the emitter, mobile and the receiver is fixed.

                   f ’’ = f’ \frac{c}{ c-v}

where c represents the sound velocity in stationary blood

therefore the received frequency is

                 f ’’ = f₀   \frac{c}{c-v}

let's simplify the expression

                f ’’ = f₀ \frac{c+v}{c-v}

                f ’’ = f₀ \frac{1 + \frac{v}{c} }{1- \frac{v}{c} }

         

b) At the low speed limit v <c, we can expand the quantity

                 (1 -x)ⁿ = 1 - x + n (n-1) x² + ...

                 ( 1- \frac{v}{c} ) ^{-1} = 1 + \frac{v}{c}

 

                f ’’ = fo ( 1+ \frac{v}{c}) ( 1 + \frac{v}{c} )

                f ’’ = fo ( 1 + 2 \frac{v}{c} + \frac{v^2}{ c^2} )

leave the linear term

               f ’’ = f₀ + f₀ 2\frac{v}{c}

the sound difference

               f ’’ -f₀ = 2f₀ v/c

               Δf = 2 f₀ \frac{v}{c}

4 0
3 years ago
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