Answer:
1 sec
Explanation:
Horizontal distance (x) = 6m
Vertical distance (y) = 1.25m
Hang time is the duration the object is in the air before it reaches maximum height.
The time of free fall is given by
t = √2y/g
g = acceleration due to gravity
t = √(2*1.25)/9.8
t = √2.5/9.8
t = 0.5secs
Hang time = 2*0.5
= 1 sec
Answer:
The force applied to make the object move
Answer: q2 = -0.05286
Explanation:
Given that
Charge q1 = - 0.00325C
Electric force F = 48900N
The electric field strength experienced by the charge will be force per unit charge. That is
E = F/q
Substitute F and q into the formula
E = 48900/0.00325
E = 15046153.85 N/C
The value of the repelled second charge will be achieved by using the formula
E = kq/d^2
Where the value of constant
k = 8.99×10^9Nm^2/C^2
d = 5.62m
Substitutes E, d and k into the formula
15046153.85 = 8.99×10^9q/5.62^2
15046153.85 = 284634186.5q
Make q the subject of formula
q2 = 15046153.85/ 28463416.5
q2 = 0.05286
Since they repelled each other, q2 will be negative. Therefore,
q2 = -0.05286
Answer:
Explanation:
From the given information:
Let the first weight be 
= 80 kg
The weight of the buddy be 
= 120 kg
The weight of Bubba be 
= 60 kg
Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:
The length of the boat be 
= 4 m
∴
We can find the center of mass of the system by using the formula:
