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Stells [14]
2 years ago
13

Which material would be a suitable insulator? O silver O gold O copper O rubber​

Physics
2 answers:
givi [52]2 years ago
7 0

Answer:

Rubber

Explanation:

Imagine yourself using a frying pan. Most times, the handles are wooden or rubber because they insulate heat. The same applies to electricity as well. The only viable answer here therefore is rubber.

Good luck! I hope this helped!

Scilla [17]2 years ago
5 0

Answer:

D, rubber

Explanation:

Metals have free electrons, and are very bad as insultators. Metals conduct electricity very well. On the other hand, rubber has no free electrons and does not conduct electricity very well

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Need help with is if u can asap
jeka94
I am guessing by what I had it is a plz don't quote me on that I could be wrong
8 0
3 years ago
A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

8 0
3 years ago
When electrons are removed from an atom, the atom becomes positively charged and is referred to as a(n)
sesenic [268]

Answer is Cation

whilst an anion is the one that is negatively charged after gaining electrons

7 0
3 years ago
A bullet is shot horizontally from shoulder height (1.5 m) with an initial speed 200 m/s. (a) How much time elapses before the b
guapka [62]
<h2>Answer: (a)t=0.553s, (b)x=110.656m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which the travel of the bullet has two components: x-component and y-component. Being their main equations as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=200m/s is the bullet's initial speed

\theta=0 because we are told the bullet is shot horizontally

t is the time since the bullet is shot until it hits the ground

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=1.5m  is the initial height of the bullet

y=0  is the final height of the bullet (when it finally hits the ground)

g=9.8m/s^{2}  is the acceleration due gravity

<h2>Part (a):</h2>

Now, for the first part of this problem, the time the bullet elapsed traveling, we will use equation (2) with the conditions given above:

0=1.5m+200m/s.sin(0) t-\frac{9.8m/s^{2}.t^{2}}{2}   (3)

0=1.5m-\frac{9.8m/s^{2}.t^{2}}{2}   (4)

Finding t:

t=\sqrt{\frac{1.5m(2)}{9.8m/s^{2}}}   (5)

Then we have the time elapsed before the bullet hits the ground:

t=0.553s   (6)

<h2>Part (b):</h2>

For the second part of this problem, we are asked to find how far does the bullet traveled horizontally. This means we have to use the equation (1) related to the x-component:

x=V_{o}cos\theta t   (1)

Substituting the knonw values and the value of t found in (6):

x=200m/s.cos(0)(0.553s)   (7)

x=200m/s(0.553s)   (8)

Finally:

x=110.656m  

4 0
4 years ago
45 points PLEASE HELP ME!!!!<br> Describe Rutherford's contribution to the atomic model
GaryK [48]
Rutherford was the first person to make a model of an atom that was mostly accurate, the only thing is in his early model there were electrons and protons, at this time Rutherford did not know of a neutron and was not discovered until 1932.<span />
7 0
3 years ago
Read 2 more answers
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