Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
36 because if you add 21 + 15 you get 36. How by adding it all together. I hope this helped you bye
Answer:
y=45x+25
Step-by-step explanation:
y=45x+25
25 is a one-time fee so it is at the end. 45 is the monthly fee so it goes in front of x.
A property of rectangles is that opposite sides are congruent. In this case, since QT and RS are opposite sides, they are equal to each other. With this knowledge, you can form the equation
to solve for x.
Firstly, subtract both sides by 8: 
Next, divide both sides by 4 and your answer will be
, or the third option.