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aalyn [17]
3 years ago
10

When aqueous solutions of chromium(III) sulfate and potassium carbonate are combined, solid chromium(aII) carbonate and a soluti

on of potassium sulfate are formed. The net ionic equation for this reaction is
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds)
Chemistry
1 answer:
enot [183]3 years ago
3 0
So confusing these questions smh
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Chemistry is best defined as the study of what
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<span>the science that systematically studies the composition, properties, and activity of organic and inorganic substances and various elementary forms of matter.

basically studying chemicals</span>
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Which of these extracellular signal molecules could diffuse through a plasma membrane and bind to an intracellular receptor?
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When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
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1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
.
C10H8  +  12O2  ---->  10CO2   + 4H2O

C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
6 0
3 years ago
Read 2 more answers
What is the maximum mass of PH3 that can be formed when 62.0g of phosphorus reacts with
Luda [366]

<u>Answer:</u> The mass of PH_3 produced is 45.22 g

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For </u>P_4<u>:</u>

Given mass of P_4 = 62.0 g

Molar mass of P_4 = 124 g/mol

Putting values in equation 1, we get:

\text{Moles of }P_4=\frac{62.0g}{124g/mol}=0.516mol

  • <u>For </u>H_2<u>:</u>

Given mass of H_2 = 4.00 g

Molar mass of H_2 = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2mol

The chemical equation follows:

P_4(g)+6H_2(g)\rightarrow 4PH_3(g)

By stoichiometry of the reaction:

If 6 moles of hydrogen gas reacts with 1 mole of P_4

So, 2 moles of hydrogen gas will react with = \frac{1}{6}\times 2=0.333mol of P_4

As the given amount of P_4 is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hydrogen gas is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 6 moles of H_2 produces 4 mole of PH_3

So, 2 moles of H_2 will produce = \frac{4}{6}\times 2=1.33mol of PH_3

We know, molar mass of PH_3 = 34 g/mol

Putting values in equation 1, we get:

\text{Mass of }PH_3=(1.33mol\times 34g/mol)=45.22g

Hence, the mass of PH_3 produced is 45.22 g

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3 years ago
What substance is acting as the Brønsted-Lowry base in the forward reaction below? H2O + HCI ----&gt; H3O+ CI-
yarga [219]
H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.
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