28/36 will be your answer which can be simplified into 14/18 which can be simplified again to 7/9 and that's your final answer
we know there are 180° in π radians, how many degrees then in -3π/10 radians?
![\bf \begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\\\ x&-\frac{3\pi }{10} \end{array}\implies \cfrac{180}{x}=\cfrac{\pi }{~~-\frac{3\pi }{10}~~}\implies \cfrac{180}{x}=\cfrac{\frac{\pi}{1} }{~~-\frac{3\pi }{10}~~} \\\\\\ \cfrac{180}{x}=\cfrac{\pi }{1}\cdot \cfrac{10}{-3\pi }\implies \cfrac{180}{x}=-\cfrac{10}{3}\implies 540=-10x\implies \cfrac{540}{-10}=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill -54=x~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20degrees%26radians%5C%5C%20%5Ccline%7B1-2%7D%20180%26%5Cpi%20%5C%5C%5C%5C%20x%26-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cpi%20%7D%7B~~-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D~~%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cfrac%7B%5Cpi%7D%7B1%7D%20%7D%7B~~-%5Cfrac%7B3%5Cpi%20%7D%7B10%7D~~%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B180%7D%7Bx%7D%3D%5Ccfrac%7B%5Cpi%20%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B10%7D%7B-3%5Cpi%20%7D%5Cimplies%20%5Ccfrac%7B180%7D%7Bx%7D%3D-%5Ccfrac%7B10%7D%7B3%7D%5Cimplies%20540%3D-10x%5Cimplies%20%5Ccfrac%7B540%7D%7B-10%7D%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20-54%3Dx~%5Chfill)
Answer:
387, or you can do it another way in the problem if you like/.
Step-by-step explanation:
3x9=27
4x9=36
36+2=38
387
There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.
Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?
If we assume that the y-intercept (b) is zero, then y = mx, and
16/3 = 1m, so that m = 16/3, and so y = (16/3)x.
First, reorder the numbers from least to greatest
1.4, 1.6, 1.7, 2.5, 2.5
The median is the middle number
1.7 is your answer
hope this helps
