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2 years ago

Explain the three forces at work that hold an atom together.

Chemistry

1 answer:

ELEN [110]2 years ago

4 0

Answer:

Electromagnetic force, Strong nuclear force, and Weak nuclear force.

Explanation:
Forces acting

electromagnetic force, strong nuclear force, and weak nuclear force. The electromagnetic force keeps the electrons attached to the atom. The strong nuclear force keeps the protons and neutrons together in the nucleus. The weak nuclear force controls how the atom decays.

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Given the number of a substance , how do you solve for the number of a moles of a substance

chubhunter [2.5K]

Given the number of a substance, we can solve the number of moles by using a conversion factor that would relate the number of a substance to the number of moles. In any case, Avogadro's number would be used. It represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. For example, we are given 1.23 x 10^24 atoms of a substance converting it to moles we do as follows:

1.23 x 10^24 atoms ( 1 mol / 6.022x10^23 atoms ) = 2.04 moles

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3 years ago

A sample of no2 occupies 16,500 ml at stp. How many no2 molecules are in the sample?.

svet-max [94.6K]

here it is! mL to Liters to moles to molecules

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2 years ago

What is the best reason for a student to remove a dangling bracelet when heating test tubes of acidic solutions in a hot-water b

allsm [11]

So it doesnt touch and create a negative reaction

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3 years ago

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sattari [20]

Answer:

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3 years ago

As the number of solute particles in a solution increases, the effect on the freezing point of the solution increases. Which ion

Ivahew [28]

Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

(3) NaCl:

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃.

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3 years ago

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