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2 years ago

What method is used by the cell to rid itself of more sodium?.

Chemistry

2 answers:

Liula [17]2 years ago

6 0

Answer:

Exocytosis helps the cell rid itself of wastes. The sodium-potassium pump requires energy to move ions across the cell membrane. Diffusion is an active process that requires a cell to expend a great deal of energy. I think

Reika [66]2 years ago

6 0

I’m probably wrong but I think it’s the sodium-potassium pump.

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3 years ago

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Which statement indicates that a substance may be an ionic compound?

lapo4ka [179]

If it has a metal and a nonmetal. Not sure if this helps, but I hope it does :)

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3 years ago

How is the periodic law demonstrated in halogens

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Halogens is defined as the group of 7 periodic table. As, every periodic table contains 7 valence electrons and they only need 1 more to complete an outer shell, that is why they are extremely reactive. And according to the law that recurring patterns of the properties of elements arise when they are arranged in order of increasing atomic number. As the halogen all act very similarly with each other in chemical reaction, it is true.

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3 years ago

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Which of the following is a buffer system? Which of the following is a buffer system? H2CO3(aq) and KHCO3(aq) NaCl(aq) and NaOH(

Readme [11.4K]

Answer:

Explanation:

A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.

In the systems:

H₂CO₃(aq) and KHCO₃(aq): Carbonic acid, H₂CO₃, is a weak acid that, in solution with its conjugate pair, HCO₃⁻ make a buffer system.

NaCl(aq) and NaOH(aq): NaCl is a salt and NaOH is a strong base. Thus, this system is not  a buffer system.

H₂O(l) and HCl(aq): Water is a solvent and HCl a strong acid. This is not a buffer system.

HCl(aq) and NaOH(aq): HCl is a strong acid and NaOH a strong base. This is not a buffer system.

NaCl(aq) and NaNO₃(aq): Both NaCl and NaNO₃ are salts and this system is not a buffer system.

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3 years ago

What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr

SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, $CH_3CH_2CH_3$ the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= $1s^{2}2s^{2}2p^{2}$

In excited state: $1s^{2}2s^{1}2p^{3}$

Hydrogen (atomic number=1): $1s^{1}$

All the bonds in the compound is single bond( $\sigma$ -bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in $1s^{1}$ of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is $s$ -hybridization and the hybridization of Carbon is $sp^{3}$ -hybridization.

The hybridization of each atom is shown in the image.

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3 years ago